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SES-FAD (Basic Algebra before Differentiation)

SES-FAD (Basic Algebra before Differentiation)

Assessment

Presentation

Mathematics

University

Medium

Created by

Thavarajah Selvarajah

Used 7+ times

FREE Resource

1 Slide • 23 Questions

1

SES-FAD (Basic Algebra before Differentiation)

by Thavarajah Selvarajah

2

Multiple Choice

Is this ready for to find  dydx?\frac{\text{d}y}{\text{d}x}?  

y=x3y=\sqrt[3]{x}  

1

Yes

2

No

3

Maybe

4

Not sure

3

Multiple Choice

Is this ready for to find  dydx?\frac{\text{d}y}{\text{d}x}?  

y=x3y=\sqrt[3]{x}  

1

Yes

2

No

3

Maybe

4

Not sure

4

Multiple Choice

In order to find  dydx,\frac{\text{d}y}{\text{d}x},   y=xy=\sqrt[]{x}  can be written as 

1

y=x12y=x^{\frac{1}{2}}  

2

y=x2y=x^2  

3

Stay as  y=xy=\sqrt[]{x}

5

Multiple Choice

In order to find  dydx,\frac{\text{d}y}{\text{d}x},   y=x3y=\sqrt[3]{x}  can be written as 

1

y=x13y=x^{\frac{1}{3}}  

2

y=x3y=x^3  

3

Stay as  y=x3y=\sqrt[3]{x}

6

Multiple Choice

Is this ready for to find  dydx?\frac{\text{d}y}{\text{d}x}?  

y=x14y=x^{\frac{1}{4}}  

1

Yes

2

No

3

Not Sure

4

Maybe

7

Multiple Choice

Can SES-FAD be applied on this? y=x2(2x+1)y=x^2\left(2x+1\right)  

1

Yes

2

No

8

Multiple Choice

Choose the correct expansion for y=x2(2x+1)y=x^2\left(2x+1\right)  

1

y=2x2+x2y=2x^2+x^2  

2

y=3x3y=3x^3  

3

y=2x3+x2y=2x^3+x^2  

4

y=2x3y=2x^3  

9

Multiple Choice

Can SES-FAD be applied for  y=x(1+2x)2y=x\left(1+2x\right)^2  

1

Yes

2

No

3

Not Sure

4

Doesnt matter

10

Multiple Choice

Can SES-FAD be applied for  y=x(x+1)y=\sqrt[]{x}\left(\sqrt[]{x}+1\right)  

1

Yes

2

No

3

Not Sure

4

Doesnt matter

11

Multiple Choice

Can SES-FAD be applied for  y=x3(2x+1)y=x^3\left(2x+1\right)  

1

Yes

2

No

3

Not Sure

4

Doesnt matter

12

Multiple Choice

Given  y=x(x+1)y=\sqrt[]{x}\left(\sqrt[]{x}+1\right)  . Choose the CORRECT expansion upon applying                     SES-FAD.

1

y=x+x12y=x+x^{\frac{1}{2}}  

2

y=x+x2y=x+x^2

3

y=x4+x2y=x^4+x^2  

4

y=x14+x12y=x^{\frac{1}{4}}+x^{\frac{1}{2}}  

13

Multiple Choice

Choose the BEST simplification to aid differentation

y=2x+1xy=\frac{2x+1}{x}  

1

y=2xx+1xy=\frac{2x}{x}+\frac{1}{x}  

2

y=(2x+1)x1y=\left(2x+1\right)x^{-1}  

3

y=1x(2x+1)y=\frac{1}{x}\left(2x+1\right)  

4

cancel xx  at 2x2x  and xx  

14

Multiple Choice

Can SES-FAD be applied on  y=x2x2+1?y=\frac{x^2}{x^2+1}?  

1

Yes

2

No

3

Maybe

4

Not Sure

15

Multiple Choice

Can SES-FAD be applied on  y=2x12x?y=\frac{2x}{1-2x}?  

1

Yes

2

No

3

Maybe

4

Not Sure

16

Multiple Choice

Can SES-FAD be applied on  y=1+x2x2?y=\frac{1+x^2}{x^2}?  

1

Yes

2

No

3

Maybe

4

Not Sure

17

Multiple Choice

Choose the BEST simplification to aid the differentiation of y=1+x2x2y=\frac{1+x^2}{x^2}  

1

y=1x2(1+x2)y=\frac{1}{x^2}\left(1+x^2\right)  

2

y=1x2+x2x2y=\frac{1}{x^2}+\frac{x^2}{x^2}  

3

Cancel the x2x^2  top and bottom

4

y=x2(1+x2)y=x^2\left(1+x^2\right)  

18

Multiple Choice

Can SES-FAD be applied on y=1(2x1)3?y=\frac{1}{\left(2x-1\right)^3}?  

1

Yes

2

No

3

Maybe

4

Not Sure

19

Multiple Choice

Can SES-FAD be applied on y=x1(2x1)3?y=\frac{x-1}{\left(2x-1\right)^3}?  

1

Yes

2

No

3

Maybe

4

Not Sure

20

Multiple Choice

Can SES-FAD be applied on y=12x3?y=\frac{1}{2x^3}?  

1

Yes

2

No

3

Maybe

4

Not Sure

21

Multiple Choice

Can SES-FAD be applied on y=12x?y=\frac{1}{2x^{ }}?  

1

Yes

2

No

3

Maybe

4

Not Sure

22

Multiple Choice

Choose the CORRECT simplification step for y=12x2y=\frac{1}{2x^2}  to ensure READY for differentiation

1

y=2x2y=2x^2  

2

y=2x2y=2x^{-2}  

3

y=12x2y=\frac{1}{2}x^{-2}  

4

y=12x2y=\frac{1}{2}x^2  

23

Multiple Choice

Choose the CORRECT simplification step for y=12xy=\frac{1}{2x^{ }}  to ensure READY for differentiation

1

y=2xy=2x^{ }  

2

y=2x1y=2x^{-1}  

3

y=12x1y=\frac{1}{2}x^{-1}  

4

y=12xy=\frac{1}{2}x^{ }  

24

Multiple Choice

Choose the CORRECT simplification step for y=3(12x)2y=\frac{3}{\left(1-2x^{ }\right)^2}  to ensure READY for differentiation

1

y=3(12x)2y=3\left(1-2x\right)^{-2}  

2

y=3(12x)2y=3\left(1-2x\right)^2

3

y=(12x)2y=\left(1-2x\right)^2

4

y=(12x)2y=\left(1-2x\right)^{-2}

SES-FAD (Basic Algebra before Differentiation)

by Thavarajah Selvarajah

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