Maths 6_2 Maths Geometry Questions 01

Maths 6_2 Geometry Questions 01

By Kewin Aljoe

​Given that the line ADB is a straight line, find the angle CDB shown below.

​Given that the line ADB is a straight line, find the angle CDB shown below.

​Give a reason for your answer.

Angles on a straight line all add together to make 180

Multiple Choice

1(a) Line 𝐴𝐷𝐵 is a straight line. Find the angle 𝐶𝐷𝐵 shown below.

Give a reason for your answer.

[2 marks}

• $$\angle\ CDB\ =\ 180\degree\ -\ 109\degree$$  Angles on a straight line all add together to make 180°

• $$\angle\ CDB\ =\ 180\degree\ -\ 109\degree$$  Angles on 3 lines all add together to make 180°

• $$\angle\ CDB\ =\ 180\degree\ -\ 109\degree$$ Angles of a triangle all add together to make 180°

• $$\angle\ CDB\ =\ 180\degree\ -\ 109\degree$$ Angles on a straight line all subtracted together to make 180°

Multiple Choice

𝐴𝐵𝐶𝐷 are points around a circle.

Find the value of 𝑥

Give a reason for your answer

• x = 360-70-100-115

  = $$75\degree$$  

  Angles around a point all add together to make 360°

• x = 360-70+100-115

  = $$75\degree$$  

  Angles around a point all add together to make 360°

• x = 360-(70-100-115)

  = $$75\degree$$  

  Angles around a point all add together to make 360°

• x = 360-70-100-115

  = $$75\degree$$  

  Angles around a point all add together to make 306°

Multiple Choice

DEF is an isosceles triangle. Find the value of y

Give a reason for your answer.

• y = 180 - 61 - 61

  Base angles in an isosceles triangle are equal and angles in a triangle add up to 180°

• y = 360 - 61 - 61

  Base angles in an isosceles triangle are equal and angles in a triangle add up to 360°

• y = 180 - 61

  Base angles in an isosceles triangle are equal and angles in a triangle add up to 180°

• y = 61

  Base angles in an isosceles triangle are equal and angles in a triangle add up to 180°

Multiple Choice

DEF is an isosceles triangle. Find the value of x

Give a reason for your answer.

• $$x+x+55\degree\ =\ 180\degree$$  

  $$2x\ =\ 180\degree\ -\ 55\degree\ =125\degree$$  

  $$x\ =\ \frac{125}{2}\ =\ 62.5\degree$$  

  Base angles in an isosceles triangle are equal and angles in a triangle add up to 180°

• $$x+x+55\degree\ =\ 180\degree$$  

  $$2x\ =\ 180\degree\ -\ 55\degree\ =125\degree$$  

  $$x\ =\ \frac{125}{2}\ =\ 62\degree$$  

  Base angles in an isosceles triangle are equal and angles in a triangle add up to 180°

• $$x+x+55\degree\ =\ 180\degree$$  

  $$2x\ =\ 180\degree\ -\ 55\degree\ =125\degree$$  

  $$x\ =\ \frac{125}{2}\ =\ 62.5\degree$$  

  Base angles in an isosceles triangle are NOT equal and angles in a triangle add up to 180°

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