Test Review Cycle 4

Test Review Cycle 4

By Bethel Naig

Copy and paste this link to open the formula chart:

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https://mydata.dallasisd.org/docs/ACP/202122_1/Formula/Geometry_1101213F.pdf​

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​Find the area of the shape

in square feet:​

​1. See that you can break down into two shapes, a trapezoid and a circle.

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2. Find the area of the two shapes.​

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Area of a trapezoid = 1/2*h*(b₁+b₂)

So, it becomes: 1/2*(8 ft)*(28+18) = 184

Area of a circle = ​πr²

So, it be​comes (3.14)(9)² = 254.3

We half it because it's half a circle = 254.3/2 = 127.2

Area composite = 127.2 + 184 = 311.2 ft²​

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Multiple Choice

Find the area of the shape in square feet. Round to the tenths place.

• 7.1 in²

• 6.7 in²

• 5.6 in²

• 3.1 in²

​Find the area of the sector of the circle:

​We use the formula to find a section or sector of a circle. We replace n with 45 degrees and r with 6 yards.

​

A = (45/360)*​π(6)²

A = 14.1​

Multiple Choice

Find the area of the sector of the circle. Round to the nearest tenth.

• 9.4 m²

• 25 m²

• 75.3 m²

• 64.3 m²

​Find the area of the hexagon:

​1. First find the perimeter.

P = the length of a side * the number of sides

P = 4*6 = 24 cm

2. Find the apothem.

Apothem is given. It's 3 cm

3. Plug into formula:

A = 1/2*(apothem)*(perimeter)

A = 1/2*(​3)*(24)

A = 36​

Multiple Choice

Find the area of the hexagon.

• 224 in²

• 336 in²

• 168 in²

• 112 in²

​Volume: Identify the shape & use the corresponding formula

​Identify the shape and then find the variables. Solve for volume.

1. This is a cylinder:

V = ​π​*r^2*h

2. Find variables.​

r or radius = 4 m

h or height = 10 m​

3. Solve for volume.

V = ​π​(4)²​(10) = 502.4 m³

Multiple Choice

Find the volume of the sphere.

• 314 in²

• 104 in²

• 63 in²

• 274 in²