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Gases Part 2: Boyle's Law and Charles's Law

Gases Part 2: Boyle's Law and Charles's Law

Assessment

Presentation

Chemistry, Science

10th - 12th Grade

Practice Problem

Medium

NGSS
HS-PS3-4

Standards-aligned

Created by

Abby Fancsali

Used 17+ times

FREE Resource

11 Slides • 9 Questions

1

Gases Part 2: Boyle's Law and Charles's Law

By Abby Fancsali

2

Introduction​

  • The Gas Laws are a set of mathematical relationships between

    • volume

    • temperature

    • pressure

    • amount of gas​

3

Section 1: Boyle's Law​

  • Robert Boyle found that doubling the pressure on a sample reduced the volume of a gas by half

    • A smaller area means gas molecules have less room and are more likely to bump into one another

  • Mathematically shown:

    • P ×​ V = k

      • k is a constant

    • P1 × V1 = P2 × V2

      • The units do not matter as long as they are the same on both sides of the equation!

4

Section 1: Boyle's Law​ Sample Problem 1

  • A Sample of Oxygen Gas has a Volume of 150.0 mL when its Pressure is 0.947 atm. What will the volume of the gas be at 0.987 atm if the volume of the gas remains constant?

    • Identify what we have

      • V1= 150

      • P1=0.947

      • V2 = ?

      • P2 =0.987

    • Plug our Values into Boyle's Law

      • 150 x 0.947 = V2 x 0.987 ​

5

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6

Section 1: Boyle's Law​ Sample Problem 2

  • A helium ballon contains 125 mL of gas at a pressure of 0.974 atm. What Volume will the gas occupy at STP (1 atm)?

    • Identify what we have

      • V1= 125

      • P1=0.974

      • V2 = ?

      • P2 =1

    • Plug our Values into Boyle's Law

      • 125 x 0.974 = V2 x 1 ​

7

Fill in the Blanks

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8

Section 1: Boyle's Law​ Sample Problem 3

  • Use Boyle's Law to solve for the missing value

    • V1= 2 x 105 L

    • P1=?

    • V2 = 1.8 x 103

    • P2 = 180 mm Hg

  • Plug our Values into Boyle's Law

    • (2 x 105) x P1 = (1.8 x 103) x 180 ​

9

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11

The Kelvin Temperature Scale

  • The Kelvin Temperature scale is used in Charles's Law

    • Convert from Celsius by adding 273 to your temperature

      • 0 ° C = 273 K

      • 100 ° C = 373 K

12

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13

Section 2: Charles's Law

  • Charles's Law looks at how Temperature affects a gas

    • When the pressure is constant, an increase in temperature also increases the volume

      • All Gases expand to the same extent when heated by the same temperature interval​

    • Mathematically: V/T = k

      • For changes:

14

Section 2: Charles's Law Sample Problem 1

  • A Sample of neon Gas occupies a volume of 752 mL at 25° C. What will the Volume be at 50° C if the pressure remains constant?

    • Step 1: Identify what we know

      • V1= 752 mL

      • T1= 25°​C

      • V2=?

      • T2= 50°C

    • Step 2 Change Temperatures to Kelvin

      • T1= 25 + 273

      • T2= 50 + 273

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17

Section 2: Charles's Law Sample Problem 1

  • A Sample of neon Gas occupies a volume of 752 mL at 25° C. What will the Volume be at 50° C if the pressure remains constant?

    • what we know

      • V1= 752 mL

      • T1= 298°​C

      • V2=?

      • T2= 323°C

    • Step 3: Plug Values into our Equation and solve for our unknown

18

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19

Section 2: Charles's Law Sample Problem 2

  • A balloon filled with Oxygen gas occupies a volume of 5.5 L at 25°C. What Volume will the balloon be at 100°C?

    • what we know°

      • V1= 5.5 L

      • T1= 25°​C + 273 = 298

      • V2=?

      • T2= 100°C+273 =373 K

    • Step 3: Plug Values into our Equation and solve for our unknown

20

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Gases Part 2: Boyle's Law and Charles's Law

By Abby Fancsali

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