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W17 Activity 1 - Ohm's Law

W17 Activity 1 - Ohm's Law

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Physics

9th - 12th Grade

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Created by

Nicholas Carrillo

Used 21+ times

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11 Slides • 10 Questions

1

W17 Activity 1

Ohm's Law

By Nicholas Carrillo

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Voltage differences cause electric charges to move

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How much charge moves through a wire per second is called electric current.

Units: Amps (A)​

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When you connect one end of a battery to the opposite end (+ to -), current will flow.

How much current will flow is based on if there is anything in between...like a light bulb!

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5

Things like lightbulbs have a resistance that limits current.

In general we call them resistors.

Units for resistance is Ohms (Ω)

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6

Multiple Choice

Which best describes what voltage does in a circuit?

1

Voltage differences cause electric charges to move through a circuit.

2

Voltage differences polarize charge in a circuit

3

Voltage differences cause lightbulbs to light up

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Multiple Choice

What are the units for voltage?

1

Volts (V)

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Amps (A)

3

Ohms ( Ω\Omega  )

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Multiple Choice

The amount of electric charge flowing per second is known as...

1

Electric Current

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Resistance

3

Voltage

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Ohms

9

Multiple Choice

What are the units for electric current?

1

Volts (V)

2

Amps (A)

3

Ohms ( Ω\Omega  )

10

Multiple Choice

Which of the following best describes resistance?

1

Resistance limits the amount of current flow

2

Resistance enhances the amount of current flow

3

Resistance pushes the electric charges back.

4

Resistance pushes the electric charges forward.

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Multiple Choice

What are the units for resistance?

1

Volts (V)

2

Amps (A)

3

Ohms ( Ω\Omega  )

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The relationship between voltage, current, and resistance is:

V = I*R​

Ohm's Law​

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Ohm's Law tells us that if we want a lot of current, we need either a lot of voltage, little resistance, or some combination of both.

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A 9V battery is connected across a lightbulb with 10Ω of resistance.

What is the current through the light bulb?

V = I*R

I = V/R

I = 9/10 = 0.9 A​

0.9A is going through the lightbulb​

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1A of current is going through a light bulb with 20Ω or resistance.

What is the voltage across the light bulb?​

​V = I*R

V = 1*20

V = 20 V

20V are across the light​bulb

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12V are put across a lightbulb, and a current of 2A flows through the light.

What is the resistance of the light bulb?

V = I*R

R = V/I

R = 12/2 = 6​Ω

​The lightbulb has a resistance of 6​Ω

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Summary

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W17 Activity 1

Ohm's Law

By Nicholas Carrillo

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