
W17 Activity 1 - Ohm's Law
Presentation
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Physics
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9th - 12th Grade
•
Medium
Nicholas Carrillo
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11 Slides • 10 Questions
1
W17 Activity 1
Ohm's Law
By Nicholas Carrillo
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Voltage differences cause electric charges to move
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How much charge moves through a wire per second is called electric current.
Units: Amps (A)
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When you connect one end of a battery to the opposite end (+ to -), current will flow.
How much current will flow is based on if there is anything in between...like a light bulb!
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Things like lightbulbs have a resistance that limits current.
In general we call them resistors.
Units for resistance is Ohms (Ω)
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Multiple Choice
Which best describes what voltage does in a circuit?
Voltage differences cause electric charges to move through a circuit.
Voltage differences polarize charge in a circuit
Voltage differences cause lightbulbs to light up
7
Multiple Choice
What are the units for voltage?
Volts (V)
Amps (A)
Ohms ( Ω )
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Multiple Choice
The amount of electric charge flowing per second is known as...
Electric Current
Resistance
Voltage
Ohms
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Multiple Choice
What are the units for electric current?
Volts (V)
Amps (A)
Ohms ( Ω )
10
Multiple Choice
Which of the following best describes resistance?
Resistance limits the amount of current flow
Resistance enhances the amount of current flow
Resistance pushes the electric charges back.
Resistance pushes the electric charges forward.
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Multiple Choice
What are the units for resistance?
Volts (V)
Amps (A)
Ohms ( Ω )
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The relationship between voltage, current, and resistance is:
V = I*R
Ohm's Law
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Ohm's Law tells us that if we want a lot of current, we need either a lot of voltage, little resistance, or some combination of both.
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A 9V battery is connected across a lightbulb with 10Ω of resistance.
What is the current through the light bulb?
V = I*R
I = V/R
I = 9/10 = 0.9 A
0.9A is going through the lightbulb
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1A of current is going through a light bulb with 20Ω or resistance.
What is the voltage across the light bulb?
V = I*R
V = 1*20
V = 20 V
20V are across the lightbulb
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12V are put across a lightbulb, and a current of 2A flows through the light.
What is the resistance of the light bulb?
V = I*R
R = V/I
R = 12/2 = 6Ω
The lightbulb has a resistance of 6Ω
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Summary
W17 Activity 1
Ohm's Law
By Nicholas Carrillo
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