Trigonometri

Multiple Choice

Sin²x = ...

• cosx - 1

• cos²x-1

• 1-cos²x

• 1 - cosx

Multiple Choice

$$\frac{1\ -\ \sec^2\ A}{1-\ \csc^2\ A}$$ Sederhanakanlah identitas trigonometri diatas. 

• $$\tan\ A$$  

• $$\cot\ A$$  

• $$\tan^2\ A$$  

• $$\tan^{4\ }A$$  

Multiple Choice

• $$\left\{20°,70°\right\}$$

• $$\left\{20°\right\}$$

• $$\left\{70°\right\}$$

• $$\left\{20°,70°,200°,250°\right\}$$

• $$\left\{40°,140°\right\}$$

Multiple Choice

• $$\left\{10°,50°,130°,170°,250°,290°\right\}$$

• $$\left\{10°,130°,250°\right\}$$

• $$\left\{50°,170°,290°\right\}$$

• $$\left\{10°,50°,130°,170°\right\}$$

• $$\left\{30°,150°\right\}$$

Multiple Choice

• $$\left\{-135°,135°\right\}$$

• $$\left\{135°,315°\right\}$$

• $$\left\{-135°,135°,315°\right\}$$

• $$\left\{45°,135°\right\}$$

• $$\left\{45°,135°,225°,315°\right\}$$

Multiple Choice

• $$\left\{35\degree,125\degree\right\}$$

• $$\left\{35\degree\right\}$$

• $$\left\{30\degree\right\}$$

• $$\left\{30\degree,130\degree\right\}$$

• $$\left\{135\degree\right\}$$

Multiple Choice

Penyelesaian dari persamaan $$2\sin^2x-\sin x-1=0$$   untuk  $$180\degree\le x\le360\degree$$  adalah ...

• $$150\degree$$  dan  $$180\degree$$  

• $$180\degree$$  dan  $$210\degree$$  

• $$210\degree$$  dan $$330\degree$$  

• $$240\degree$$  dan  $$270\degree$$  

• $$300\degree$$  dan $$330\degree$$  

Multiple Choice

Diketahui  $$\sin\ x\ \cos\ x\ =\ \frac{3}{8}$$  . Nilai  $$\frac{1}{\sin x}-\ \frac{1}{\cos\ x}$$  adalah ............

• $$\frac{2}{4}$$  

• $$\frac{4}{3}$$  

• $$\frac{3}{4}$$  

• $$\frac{1}{4}$$  

Multiple Choice

Hasil penyelesaian dari ( cotan²x - cos²x) tan⁴x...

• sin²x + cos^2x

• cos²x

• sin²x

• sin²x + cotan²x

Multiple Choice

nilai dari  $$\frac{2\ \tan x}{1\ +\tan^2x}$$  ...

• 2 cos x . sin x

• $$\frac{2\ \tan\ x}{1+\tan^2x}$$  

• 3 sin x . cos x

• 2 sin x . cos x

Multiple Choice

$$\frac{\sin^2\alpha-\sin^2\beta}{\cos\ \alpha\ \cos^2\beta}\ nilainya\ adalah$$  

• $$\tan^2\beta-\tan^2\alpha$$  

• $$\tan^2\alpha-\tan^2\beta$$  

• $$\sin^2\alpha-\cos^2\beta$$  

• $$\frac{\sin^2\beta}{\cos^2\alpha\ \cos^2\beta}$$