
even and odd functions
Presentation
•
Mathematics
•
9th - 12th Grade
•
Practice Problem
•
Medium
Standards-aligned
Diana Rodriguez
Used 51+ times
FREE Resource
10 Slides • 16 Questions
1
Even and Odd functions
Even Functions
A function is said to be even if its graph is symmetric with respect to the the y-axis. f(-x)=f(x)
Some text here about the topic of discussion
2
Even and odd functions
Odd Functions
A function is said to be odd if its graph is symmetric with respect to the origin. f(-x)=-f(x)
Some text here about the topic of discussion
3
Multiple Choice
An even function is symmetric with respect to the...
y-axis
x-axis
origin
4
Multiple Choice
An odd function is symmetric with respect to...
the y-axis
the x-axis
the origiin
5
Notice that in an even function, the sign of the x coordinate will change, for example the points (2,5) and (-2,5) will appear in the same even function.
Some text here about the topic of discussion.
6
Notice that in an odd function, the signs of the x-coordinate and y-coordinate will change, for example; the points (2,5) and (-2,-5) are the points of an odd function.
Some text here about the topic of discussion.
7
Determine whether a function is even or odd graphically
The following graph is even, because is you fold it over the y-axis, the left and right sides will match
Some text here about the topic of discussion
8
Determine whether a function is even or odd graphically
The following graph is odd, because is you fold it over the origin, both parts will match
Some text here about the topic of discussion
9
Determine whether a function is even or odd graphically
Some text here about the topic of discussion
The following graph is neither even nor odd because if you fold it over the origin or the y-axis the points will not match
10
Multiple Choice
Determine whether the graph is even, odd or neither
even
odd
neither
11
Multiple Choice
Determine whether the graph is even, odd or neither
even
odd
neither
12
Multiple Choice
Determine whether the graph is even, odd or neither
even
odd
neither
13
Multiple Choice
Determine whether the graph is even, odd or neither
even
odd
neither
14
Multiple Choice
Determine whether the graph is even, odd or neither
even
odd
neither
15
Fill in the Blank
Type answer...
16
Fill in the Blank
Type answer...
17
How to determine whether a funtion is even or odd analytically
Ex: Decide whether the function is even, odd or neither
g(x)=x3-x
Solution: Replace x for -x
g(-x)= (-x)3-(-x)= -x3+x
Now compare the signs of all terms in the new function with the original function, if all signs change, is an ODD function
Some text here about the topic of discussion
18
How to determine whether a funtion is even or odd analytically
Ex: Decide whether the function is even, odd or neither
g(x)= x4+x2+1
Solution: Replace x for -x
g(-x)= (-x)4+ (-x)2 + 1= x4+x2+1
Now compare the signs of all terms in the new function with the original function, if all signs remain the same, is an EVEN function
Some text here about the topic of discussion
19
How to determine whether a funtion is even or odd analytically
Ex: Decide whether the function is even, odd or neither
g(x)= x4+x3
Solution: Replace x for -x
g(-x)= (-x)4+ (-x)3 = x4-x3
Now compare the signs of all terms in the new function with the original function, if only some signs change, NEITHER
Some text here about the topic of discussion
20
Multiple Choice
Determine whether the function f(x)=x6−2x2+3
even
odd
neither
21
Multiple Choice
Determine whether the function f(x)=x3−5
even
odd
neither
22
Multiple Choice
Determine whether the function f(x)=x3−5x
even
odd
neither
23
Multiple Choice
Determine whether the function f(x)=x1−x2
even
odd
neither
24
Multiple Choice
Determine whether the function f(t)=t2+2t−3
even
odd
neither
25
Multiple Choice
Determine whether the function f(s)=4s32
even
odd
neither
26
Open Ended
Write using your own words what you learned today about even and odd functions
Even and Odd functions
Even Functions
A function is said to be even if its graph is symmetric with respect to the the y-axis. f(-x)=f(x)
Some text here about the topic of discussion
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