
Unit 1.3 Projectile Motion Lesson
Presentation
•
Physics
•
11th - 12th Grade
•
Hard
Standards-aligned
Robert Johnson
Used 10+ times
FREE Resource
2 Slides • 14 Questions
1
2
Multiple Choice
A projectile is launched at 68.0° above the horizontal and at a speed of 55 m/s. How long will it take the projectile to reach maximum height?
1.8 s
3.2 s
4.5 s
5.2 s
3
Multiple Choice
A projectile is launched at 68.0° above the horizontal and at a speed of 55 m/s. What is the maximum height reached by the projectile?
233 m
158 m
2.6 m
133 m
4
Multiple Choice
A projectile is launched at 68.0° above the horizontal and at a speed of 55 m/s. What is the projectile's x-component of velocity at the maximum height?
39 m/s
55.7 m/s
20.6 m/s
32.3 m/s
5
Multiple Choice
A projectile is launched at 68.0° above the horizontal and at a speed of 55 m/s. What is the horizontal displacement at maximum height?
124 m
116 m
222 m
107 m
6
7
Multiple Choice
If h(t)=−16t2+84t+140 , what is the value used for gravity?
-16
-32
-9.8
-4.9
8
Multiple Choice
If h(t)=−16t2+84t+140 , what is the initial velocity?
84 feet
84 feet per second
140 feet
140 feet per second
9
Multiple Choice
If h(t)=−16t2+84t+140 , what is the initial height?
84 feet
84 feet per second
140 feet
140 feet per second
10
Multiple Choice
If h(t)=−4.9t2+18t+43 , what is the value used for gravity?
-16
-32
-9.8
-4.9
11
Multiple Choice
If h(t)=−4.9t2+18t+43 , what is the initial velocity?
18 meters per second
18 meters
43 meters per second
43 meters
12
Multiple Choice
If h(t)=−4.9t2+18t+43 , what is the initial height?
18 meters per second
18 meters
43 meters per second
43 meters
13
Multiple Choice
Write the function that models the path of an object thrown from a height of 12 feet with an intial velocity of 19 feet/sec.
h(t)=−16t2+12t+19
h(t)=−4.9t2+19t+12
h(t)=−4.9t2+12t+19
h(t)=−16t2+19t+12
14
Multiple Choice
Write the function that models the path of an object thrown from a height of 25 meters with an initial velocity of 40 meters/sec.
h(t)=−16t2+25t+40
h(t)=−4.9t2+25t+40
h(t)=−4.9t2+40t+25
h(t)=−16t2+40t+25
15
Multiple Choice
An object's path is modeled by: h(t)=−16t2+150t+100 HOW LONG until max height?
451.6 seconds
4.7 seconds
100 seconds
10 seconds
16
Multiple Choice
An object's path is modeled by: h(t)=−16t2+150t+100 WHAT is the max height?
451.6 feet
4.7 feet
100 feet
10 feet
Show answer
Auto Play
Slide 1 / 16
SLIDE
Similar Resources on Wayground
11 questions
Significant Figures
Presentation
•
10th - 12th Grade
10 questions
Vector Addition and Subtraction
Presentation
•
11th - 12th Grade
12 questions
Tres Leyes de Newton
Presentation
•
KG
12 questions
SECOND CONDITIONAL
Presentation
•
12th Grade
11 questions
Pengantar Listrik Searah
Presentation
•
12th Grade
12 questions
Resistors in Series and Parallel
Presentation
•
11th - 12th Grade
10 questions
LEY DE COULOMB
Presentation
•
11th Grade
11 questions
Atwood Machines
Presentation
•
11th - 12th Grade
Popular Resources on Wayground
11 questions
Hallway & Bathroom Expectations
Quiz
•
6th - 8th Grade
10 questions
HCS SCI 03 Summer School Assessment 2
Quiz
•
3rd Grade
11 questions
Home Scope
Quiz
•
7th - 8th Grade
12 questions
2026 TAP Technology in the Classroom
Presentation
•
Professional Development
15 questions
HCS SCI 05 Summer School Assessment 2 Review
Quiz
•
5th Grade
15 questions
HCS SCI 04 Summer School Review 2
Quiz
•
4th Grade
59 questions
Geometry Unit 3 Review
Quiz
•
9th - 12th Grade
14 questions
FAST ELA READING SMAPLE TEST MATERIALS
Passage
•
3rd Grade