
Solving Quadratic equations by Factoring
Presentation
•
Mathematics
•
9th - 12th Grade
•
Practice Problem
•
Medium
Standards-aligned
Nakeyta Coleman
Used 20+ times
FREE Resource
15 Slides • 11 Questions
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Solving Quadratic Equations by Factoring
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For every problem, follow these steps. Write them down!!!
1. Make sure the equation is equal to zero.
2. Factor the left side of the equation (using one of these methods we learned in the last unit: trinomials where a=1, GCF, difference of squares, or trinomials where a>1). This one is a trinomial where a=1, so we just needed to find what multiplied to -8 and added to -2.
3. Set each factor equal to zero and solve for x. (This is what you practiced yesterday!)
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Let's See Another:
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So from before:
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Multiple Choice
Solve the equation using the zero product property.
3x(2x - 4) = 0
x = -1/3 or x = -2
x = 0 or x = 2
x = 0 or x = -2
x = -1/3 or x = 2
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Multiple Choice
Factor 6x2-27x
(6x+1)(x+3)
3x(2x-9)
6x(x-9)
(3x-9)(2x+3)
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Multiple Choice
Solve: x2 - 81 = 0
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9, -9
3, -3, 9, -9
None of the above
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Multiple Choice
Solve
16a2 - 9 = 0
a = -3/4, 3/4
a = -4/3, 4/3
a = -9/16, 9/16
a = -16/9, 16/9
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Multiple Choice
b=4/5, b=3
b=4, b=-3
b=1/5, b=3
b=4/5, b=-3
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Multiple Choice
Solve
x2 + 9x + 20 = 0
x = -2, x = -10
x = -3, x = -4
x = -4, x = -5
x = -4, x = -6
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Multiple Choice
Solve. 7m2 - 12m + 5 = 0
x = 5/7 and x = 1
x = 8/3 and x = 2
x = 8/3 and x = -1/2
x = -2/3 and x = -5
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Multiple Choice
Solve 2x² - 7x + 6 = 0 by factoring
x = -3/2 and x = -2
x = -3 and x = -2
x = 3 and x = 2
x = 3/2 and x = 2
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Multiple Choice
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Multiple Choice
Solve
16a2 - 9 = 0
a = -3/4, 3/4
a = -4/3, 4/3
a = -9/16, 9/16
a = -16/9, 16/9
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Multiple Choice
Solve by factoring: 2x2+ 7x + 6 = 0
x= 3/2 and x = 2
x = -3/2 and x = -2
x = 6 and x = 7
x = -6 and x = -7
Solving Quadratic Equations by Factoring
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