Latihan 1

CIC

PEMBAHASAN SOAL 1

NO. 1

maka a adalah kelipatan dari 3, sehingga a = 3k

15k = 105
k = 105/15 = 7

a = 3k = 3 x 7 = 21

NO.2

NO.3

39 = 5 x 1 + 34 = 5 x 2 + 29 = 5 x 3 + 24 = 5 x 4 + 19
= 5 x 5 + 14 = 5 x 6 + 9

49 = 5 x 1 + 44 = 5 x 2 + 39 = 5 x 3 + 34 = 5 x 4 + 29
= 5 x 5 + 24 = 5 x 6 + 19 = 5 x 7 + 14 = 5 x 8 + 9

NO.4

= 1,.. < q < 9

= 2 <= q < 9

{2,3,4,5,6,7,8}= 7 bilangan yang memenuhi

q adalah bilangan asli

NO.5

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