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PreCalculus Lesson 4

PreCalculus Lesson 4

Assessment

Presentation

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Mathematics

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10th Grade

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Practice Problem

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Medium

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CCSS
HSG.GPE.A.3, HSG.GPE.A.2, HSG.GPE.A.1

Standards-aligned

Created by

Glydyl Galleposo

Used 2+ times

FREE Resource

37 Slides • 12 Questions

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Multiple Choice

Is formed when a vertical plane intersects a double-napped cone

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ellipse

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circle

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hyperbola

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parabola

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media

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Multiple Choice

Question image

Label: What is number 1?

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center

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transversal axis

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vertex

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focus

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Multiple Choice

Question image

Label: What is number 2?

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center

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transversal axis

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vertex

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focus

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Multiple Choice

Question image

Label: What is number 3?

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center

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transversal axis

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vertex

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focus

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Multiple Choice

Question image

Label: What is number 4?

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conjugal axis

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transversal axis

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focal distance

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principal axis

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Multiple Choice

Question image

Label: What is number 5?

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conjugal axis

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a

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b

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c

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Multiple Choice

Question image

Label: What is number 6?

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conjugal axis

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a

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b

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c

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Multiple Choice

Question image

Label: What is number 7?

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conjugal axis

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a

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b

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c

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Multiple Choice

Which standard form of an equation when the transverse axis is at the origin and in y-axis?

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x2a2−y2b2=1\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

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y2a2−x2b2=1\frac{y^2}{a^2}-\frac{x^2}{b^2}=1

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Multiple Choice

Which standard form of an equation when the transverse axis is at the origin and in x-axis?

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x2a2−y2b2=1\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

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y2a2−x2b2=1\frac{y^2}{a^2}-\frac{x^2}{b^2}=1

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Multiple Choice

Which standard form of an equation when the transverse axis is at a certain point or (h,k) and is horizontal?

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(x−h)2a2−(y−k)2b2=1\frac{\left(x-h\right)^2}{a^2}-\frac{\left(y-k\right)^2}{b^2}=1

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(y−k)2a2−(x−h)2b2=1\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}=1

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Multiple Choice

Which standard form of an equation when the transverse axis is at a certain point or (h,k) and is vertical?

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(x−h)2a2−(y−k)2b2=1\frac{\left(x-h\right)^2}{a^2}-\frac{\left(y-k\right)^2}{b^2}=1

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(y−k)2a2−(x−h)2b2=1\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}=1

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