
Force and motion
Presentation
•
Science
•
10th Grade
•
Practice Problem
•
Hard
+4
Standards-aligned
OS .
Used 2+ times
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25 Slides • 0 Questions
1
Force and Motion
Lesson 1
2
Focus Question
What causes a change in motion?
3
New Vocabulary
force
system
free-body diagram
net force
Newton’s second law
Newton’s first law
inertia
equilibrium
4
Review Vocabulary
acceleration: the rate at which the velocity of an
object changes
5
• In physics, a force is a push or a pull.
• If you push harder on an object, you have a greater
effect on its motion.
• All accelerations are the result of an unbalanced
force acting on an object.
Force
6
• The direction in which force is exerted matters. The
acceleration is in the same direction as the
unbalanced force.
size and direction of a force, while F represents only
the magnitude.
Force
7
• System: objects of interest
• External world: Everything
around the object that exerts
forces
• Forces result from interactions:
Force is the agent of interaction
Force
8
• A contact force exists when an
object from the external world
touches a system and thereby
exerts a force on it.
• Field forces are exerted without
contact.
Force
9
• A physical representation that shows the forces
acting on a system is called a free-body diagram.
Force
10
• Vector sum of all the forces on an object is net force.
• When forces are in the same direction
• When forces are in opposite
directions
Combining Forces
F1 = 20 N
F2 = 30 N
F net = 50 N
F net = 10 N
F1 = 20 N
F2 = 30 N
11
Combining Forces
F1
F2
F1
F2
F
𝐹 =
𝐹1
2 + 𝐹2
2 + 2. 𝐹1𝐹2𝑐𝑜𝑠𝜃
12
• Newton’s second law states that the acceleration of
an object is proportional to the net force acting on
the object and inversely proportional to the mass of
the object.
Newton’s Second Law
13
• To use Newton’s second law to solve a problem,
follow these steps.
•
Draw a free-body diagram showing the direction
and relative strength of each force acting on the
system.
Then add the force vectors to find the net force.
Next, use Newton’s second law to calculate the
acceleration.
Use what you know about accelerated motion to
find the velocity or position of the object.
Newton’s Second Law
14
Use with Example Problem 1.
Problem
Kwaku pushes one end of a table with a force of
15.0 N. Salali pushes on the other end of the table
with a force of 20.0 N. What is the net force on
the table?
Response
●
20.0 N
15.0 N
net
Kwaku
Salali
15.0 N
20.0 N
5.0 N
=
+
=
−
= −
F
F
F
SKETCH AND ANALYZE THE PROBLEM
•Draw the situation and a free-body
diagram.
•Identify the knowns and unknowns.
SOLVE FOR THE UNKNOWN
•Determine the net force.
That is, Fnet = 5.0 in the direction Salali is
pushing.
KNOWN
UNKNOWN
FKwaku = 15.0 N
Fnet = ?
FSalali = −20.0 N
EVALUATE THE ANSWER
•The net force is in the direction of the
force with the large magnitude.
15
• In the absence of a net force, the motion (or lack of
motion) of both the moving object and the stationary object continues as it was.
• Newton’s first law is that an object that is at rest will
remain at rest, and an object that is moving will continue to move in a straight line with constant speed, if and only if the net force acting on that object is zero.
• Newton’s first law is sometimes called the law of
inertia.
Newton’s First Law
16
• Inertia is the tendency of an object to resist changes
in velocity.
• If the net force on an object is zero, then the object
is in equilibrium.
• If there is no net force acting on the object, then the
object does not experience a change in speed or
direction and is in equilibrium.
Newton’s First Law
17
• When you exert a force on your friend to push him
forward (FA on B), he exerts an equal and opposite force
on you (FB on A), which causes you to move backward.
• The forces FA on B and FB on A are an interaction pair.
• An interaction pair is two forces that are in opposite
directions, have equal magnitudes, and act on
different objects.
Interaction Pairs
18
• Newton’s third law states that all forces come in pairs
and that the two forces are equal in strength, opposite
in direction, and act on different objects.
Interaction Pairs
19
• When identifying interaction pairs, remember that they
always occur in two different free-body diagrams and
they always have symmetry in the subscripts.
Interaction Pairs
20
Use with Example Problem 4.
Problem
You are walking along when you slip on some ice
and fall. For a moment you are in free fall. During
this time, what force do you exert on Earth if your
mass is 55 kg?
(
)(
)
you on Earth
Earth on you
you
55 kg
9.8 N/kg
540 N
m
= −
= −
= −
−
=
F
F
g
Response
ANALYZE AND SKETCH THE PROBLEM
•Draw the situation and a free-body diagram.
•Identify the knowns and unknowns.
SOLVE FOR THE UNKNOWN
•Use Newton’s third law and the
definition of weight to determine the
force you exert on Earth.
EVALUATE THE ANSWER
•The force you exert on Earth is equal in
magnitude and opposite in direction to the
force Earth exerts on you.
KNOWN
UNKNOWN
myou = 55 kg
Fyou on Earth = ?
g = −9.8 N/kg
FEarth on you
●
Fyou on Earth
●
Interaction pair
21
Quiz
v
D
F
C
a
B
F
A
Which symbol represents the size and magnitude
of a force?
1.
CORRECT
22
Quiz
the unknown
D
the system
C
Which is the term for the object or objects of
interest in a free-body diagram?
2.
CORRECT
the external world
A
the vector
B
23
Quiz
the system
D
the net force
C
the acceleration
B
the external world
A
Which is the vector sum of all the forces on an
object?
3.
CORRECT
24
Quiz
Newton’s second law
D
law of inertia
C
law of equilibrium
B
Newton’s first law
A
Which law is represented by the formula?
4.
CORRECT
net
m
= F
a
25
Quiz
mass
D
acceleration
C
force
B
inertia
A
Which is the tendency of an object to resist
changes in velocity?
5.
CORRECT
Force and Motion
Lesson 1
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