Pembelajaran Peluang Suatu Kejadian Kelas 9G

• Ruang sampel = {(A,A), (A,G), (G,A), (G,G)}

• n(S) = 4

• Kejadian A = muncul keduanya angka = {(A,A)}

• n(A) = 1

• P(A) = n(A)/n(S) = 1/4

• n(S) = 52

• Kejadian A = terambil kartu As

• n(A) = 4

• Kejadian B = terambil kartu King

• n(B) = 4

• P(A atau B) = P(A) + P(B) = 4/52 + 4/52 = 8/52 = 2/13

• n(S) = 5 + 3 + 2 = 10

• Kejadian A = terambil bola merah

• n(A) = 5

• Kejadian B = terambil bola kuning

• n(B) = 3

• P(A atau B) = P(A) + P(B) = 5/10 + 3/10 = 8/10 = 4/5

• n(S) = 6 x 6 = 36

• Kejadian A = muncul jumlah mata dadu 9 = {(3,6), (4,5), (5,4), (6,3)}

• n(A) = 4

• Kejadian B = muncul jumlah mata dadu 10 = {(4,6), (5,5), (6,4)}

• n(B) = 3

• P(A atau B) = P(A) + P(B) = 4/36 + 3/36 = 7/36

Penyelesaian:

• Ruang sampel = {1, 2, 3, 4, 5, 6}

• n(S) = 6

• Kejadian A = muncul mata dadu ganjil = {1, 3, 5}

• n(A) = 3

• P(A) = n(A)/n(S) = 3/6 = 1/2