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Quadratic Transformations Lesson

Quadratic Transformations Lesson

Assessment

Presentation

Mathematics

9th Grade

Practice Problem

Easy

Created by

Kenzie-Lou Bramblett

Used 9+ times

FREE Resource

7 Slides • 6 Questions

1

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2

Draw

BELL RINGER:

Draw a flower with color.

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4

Labelling

Label the vertex form with the correct variables.

Drag labels to their correct position on the image

a

h

k

f(x)

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6

Categorize

Options (6)

f(x)=x2+ 5f\left(x\right)=x^2+\ 5  

y = 2(x+5)24y\ =\ -2\left(x+5\right)^2-4  

f(x)=12x26f\left(x\right)=\frac{1}{2}x^2-6  

y=(x2)2y=-\left(x-2\right)^2  

f(x)=35(x+4)2f\left(x\right)=\frac{3}{5}\left(x+4\right)^2  

y=32(x4)2+6y=\frac{3}{2}\left(x-4\right)^2+6  

Drag the equations to the correct transformation.

Shift up
Shift down
No vertical shift

7

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8

Categorize

Options (6)

f(x)=x2+ 5f\left(x\right)=x^2+\ 5  

y = 2(x+5)24y\ =\ -2\left(x+5\right)^2-4  

f(x)=12x26f\left(x\right)=\frac{1}{2}x^2-6  

y=(x2)2y=-\left(x-2\right)^2  

f(x)=35(x+4)2f\left(x\right)=\frac{3}{5}\left(x+4\right)^2  

y=32(x4)2+6y=\frac{3}{2}\left(x-4\right)^2+6  

Drag the equations to the correct transformation.

Shift right
Shift left
No horizontal shift

9

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10

Categorize

Options (6)

f(x)=x2+ 5f\left(x\right)=x^2+\ 5  

y = 2(x+5)24y\ =\ -2\left(x+5\right)^2-4  

f(x)=12x26f\left(x\right)=\frac{1}{2}x^2-6  

y=(x2)2y=-\left(x-2\right)^2  

f(x)=35(x+4)2f\left(x\right)=\frac{3}{5}\left(x+4\right)^2  

y=32(x4)2+6y=\frac{3}{2}\left(x-4\right)^2+6  

Drag the equations to the correct transformation.

Reflection
No Reflection

11

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12

Categorize

Options (6)

f(x)=x2+ 5f\left(x\right)=x^2+\ 5  

y = 2(x+5)24y\ =\ -2\left(x+5\right)^2-4  

f(x)=12x26f\left(x\right)=\frac{1}{2}x^2-6  

y=(x2)2y=-\left(x-2\right)^2  

f(x)=35(x+4)2f\left(x\right)=\frac{3}{5}\left(x+4\right)^2  

y=32(x4)2+6y=\frac{3}{2}\left(x-4\right)^2+6  

Drag the equations to the correct transformation.

Narrow
Wide
No Stretch/Compress

13

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Don't lose it! You can use on the quiz. :)

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