
Solving Exponential Equations Using Logarithms
Presentation
•
Mathematics
•
11th Grade
•
Hard
James Gonzalez
FREE Resource
12 Slides • 9 Questions
1
Let's use logarithms to solve equations!

2
Sometimes we are given a problem where x is in the exponent and we'll need to use logarithms to solve for x.
See how we can use the inverse of -2 to cancel the +2?
3
Now we have to "un-do" the exponent
We now know the inverse of exponent is logarithm!!
So we "take the log" of both sides (I know, super fancy sounding!!)
THEN, x-5 is no longer an exponent, and can move to the front of the equation!
NOW, we can continue solving!
4
Multiple Select
One more...
7(x+3)=46
x=log(39)−3
x=log(7)−3log(46)
x=log(7)log(46)−3
x=log746−3
5
We can write our answer in multiple ways!!
6
We need a way to go back and forth between base 10 and other bases.
This is called the CHANGE OF BASE formula!
7
Desmos will evaluate logarithms, whether they simplify to whole numbers or not!
This also shows you WHERE to find the log buttons in the Desmos keyboard! (Or you can type it out as log)
8
Multiple Choice
Solve this one!
3⋅4x−1=24
x=1
x=log4log8+1
x=log4log21+1
x=1.5
9
This is how the last problem should be solved!!
10
Multiple Choice
Solve:
5(6)3x=20
2.3
.26
.04
4
11
Multiple Choice
12
Multiple Choice
13
Multiple Choice
Solve for x.
3(n−7)−3=24
3
8
10
No solution
14
Second Method: When there is an exponent on only ONE side.
15
Multiple Choice
16
Multiple Choice
17
Multiple Choice
Solve the equation:
62x=6(−x−1)
−31
815
5
1019
18
19
Solve, giving your answers correct to 3 significant figures.
52x+1=7
log 52x+1=log 7
(2x+1)log 5=log 7
2x log 5+log 5=log 7
x=log 7−log 5/2 log 5
x=0.105
20
Solve, giving your answers correct to 3 significant figures.
32x = 4x+5
log 32x = log 4x+5
2x log 3 = (x+5)log 4
2x log 3 = x log 4+5 log 4
x(2 log 3−log 4)=5 log 4
x=5 log 4/2 log 3−log 4
x=8.55
21
Isolate the base
Take the Logarithm of both sides
Bring the exponent to the front
Continue solving!
Let's use logarithms to solve equations!

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