Search Header Logo
Trig Identity

Trig Identity

Assessment

Presentation

•

Mathematics

•

10th - 12th Grade

•

Hard

Created by

James Gonzalez

FREE Resource

14 Slides • 15 Questions

1

What are Trig Identities?

2

Reciprocal Identities: 

3

Quotient Identities:

4

Multiple Select

Which statements are true?

1

sin⁡x=1cos⁡x\sin x=\frac{1}{\cos x}

2

tan⁡2x=sin⁡2xcos⁡x\tan^2x=\frac{\sin^2x}{\cos x}

3

sec⁡x=1cos⁡x\sec x=\frac{1}{\cos x}

4

cot⁡x=cos⁡xsin⁡x\cot x=\frac{\cos x}{\sin x}

5

csc⁡2x=1sin⁡2x\csc^2x=\frac{1}{\sin^2x}

5

Pythagorean identity #1:

media

6

Pythagorean Identity #2

7

Pythagorean Identity #3

8

Anymore Pythagorean Identities??

Yes! Even more pythagorean identities can be obtained by rearranging (adding/subtracting) within the 3 identities we just covered!


See if you can figure out what they are from the following questions....

9

Multiple Choice

Rearrange:  sin⁡2x+cos⁡2x=1\sin^2x+\cos^2x=1  to solve for:   sin⁡2x\sin^2x   

1

sin⁡2x=1−cos⁡2x\sin^2x=1-\cos^2x  

2

sin⁡2x=1+cos⁡2x\sin^2x=1+\cos^2x  

3

sin⁡2x=cos⁡2x−1\sin^2x=\cos^2x-1  

10

Multiple Choice

Rearrange:  sin⁡2x+cos⁡2x=1\sin^2x+\cos^2x=1  to solve for  cos⁡2x\cos^2x  

1

cos⁡2x=1−sin⁡2x\cos^2x=1-\sin^2x  

2

cos⁡2x=1+sin⁡2x\cos^2x=1+\sin^2x  

3

cos⁡2x=sin⁡2x−1\cos^2x=\sin^2x-1  

11

Multiple Choice

Rearrange to solve for tan⁡2θ\tan^2\theta : 
                                        1 + tan⁡2θ= sec⁡2θ1\ +\ \tan^2\theta=\ \sec^2\theta  

1

tan2θ = sec2θ + 1

2

tan2θ = sec2θ - 1

3

tanθ = secθ - 1

4

tan2θ = opp/adj

12

Multiple Choice

Rearrange so it equals 1: 
                                        1 + tan⁡2x= sec⁡2x1\ +\ \tan^2x=\ \sec^2x  

1

tan⁡2x−sec⁡2x=1\tan^2x-\sec^2x=1  

2

sec⁡2x−tan⁡2x=1\sec^2x-\tan^2x=1  

3

sec⁡2x+tan⁡2x=1\sec^2x+\tan^2x=1  

4

tan⁡2x−1=sec⁡2x\tan^2x-1=\sec^2x  

13

Multiple Choice

Solve the following for  cot⁡2θ\cot^2\theta  :
1+cot⁡2θ=csc⁡2θ1+\cot^2\theta=\csc^2\theta  


1

1 = cot2θ + csc2θ

2

cot2θ =1 - csc2θ

3

cot2θ = csc2θ -1

4

cot2θ = adj/opp

14

Multiple Choice

Rearrange so it equals 1 :
1+cot⁡2θ=csc⁡2θ1+\cot^2\theta=\csc^2\theta  


1

1=cot⁡2θ+csc⁡2θ1=\cot^2\theta+\csc^2\theta

2

cot⁡2θcsc⁡2θ=1\frac{\cot^2\theta}{\csc^2\theta}=1  

3

cot⁡2θ−csc⁡2θ=1\cot^2\theta-\csc^2\theta=1  

4

csc⁡2θ−cot⁡2θ=1\csc^2\theta-\cot^2\theta=1  

15

IN CASE YOU DIDN'T GET THEM....HERE ARE ALL THE PYTHAGOREAN ARRANGEMENTS!


media

16

How do we use these identities?

media

17

Multiple Choice

Exchange each term with an identity then use algebra to reduce:

                                 tan⁡xsec⁡x\frac{\tan x}{\sec x}

1

cos⁡x\cos x  

2

csc⁡x\csc x  

3

cot⁡x\cot x  

4

sin⁡x \sin x\  

18

19

Multiple Choice

Now try this one.  Again reduce by substituting with identities:
(sec⁡x)(cot⁡x)(sin⁡x)\left(\sec x\right)\left(\cot x\right)\left(\sin x\right)

1

sin x

2

- sin x

3

1

4

-1

20

Simplifying Suggestions
  • Here are some common techniques for simplifying trig expressions

  • Notice you will be using algebra to help reduce

  • Let's look at more problems using these suggestions......

media

21

Multiple Choice

Reduce by substituting with identities:

tan⁡ x cot⁡x −cos⁡2x\tan\ x\ \cot x\ -\cos^2x  

1

tanx

2

cotx

3

sin2x

4

cos2x

22

23

Now try some on your own using the hints provided....

​

24

Multiple Choice

Simplify by factoring out a GCF first. Look at what you have left.  Can you replace with an identity?

cos⁡3x+sin⁡2xcos⁡x\cos^3x+\sin^2x\cos x

1

sin⁡x\sin x  

2

cos⁡x\cos x  

3

tan⁡x\tan x  

4

1

25

Multiple Choice

Distribute then exchange with identities:
sin⁡x(sec⁡x−csc⁡x)\sin x\left(\sec x-\csc x\right)

1

1−tan⁡x1-\tan x  

2

tan⁡x−1\tan x-1  

3

1−cot⁡x1-\cot x  

4

sin⁡x\sin x  

26

Multiple Choice

Simplify by first splitting into 2 fractions: (Note:  you CANNOT cross out anything until you've done this!)

cos⁡x−sin⁡xsin⁡xcos⁡x\frac{\cos x-\sin x}{\sin x\cos x}  

1

csc⁡x−sec⁡x\csc x-\sec x  

2

1

3

0

4

sec⁡x−csc⁡x\sec x-\csc x  

27

Multiple Choice

Substitute then find a common denominator so you can combine into 1 fraction:              cos⁡x+sin⁡xtan⁡x\cos x+\sin x\tan x  

1

csc x

2

sec x

3

1/sec x

4

cos x

28

Multiple Choice

Exchange each with identities, then get a common denom. on the bottom.  Once you have a complex fraction, flip and multiply.

    csc⁡xcos⁡xtan⁡x+cot⁡x\frac{\csc x\cos x}{\tan x+\cot x}  

1

cos²x

2

sin²x

3

cot²x

4

tan²x

29

Now you know the basics!
  • Tips for success:

  • Memorize the identities so you can recall them quickly!

  • Don't give up! There may be more than one way to simplify.

  • Keep practicing! You got this!

media
pattern-tertiary
What are Trig Identities?

Show answer

Auto Play

Slide 1 / 29

SLIDE