
Factoring by Grouping (Online Tutorial #19)
Presentation
•
Mathematics
•
8th Grade
•
Easy
+1
Standards-aligned
Robert Dohnal
Used 2+ times
FREE Resource
16 Slides • 5 Questions
1
Factor by Grouping
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Factoring by Grouping
Step by Step Guide
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STEP ONE
Factor out the GCF of all four terms
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STEP TWO
Group the first two terms together and then the last two terms together.
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STEP THREE
Factor out the GCF from each separate binomial.
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STEP FOUR
Factor out the common binomial.
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STEP 5
Check whether any of your factors can be factored further.
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STEP 6
If you factor and don't have a common binomial, then regroup your terms.
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Multiple Choice
Factor: 6x2 + 21x + 4x + 14
(3x - 2)(2x - 7)
4(2x + 5)(3x - 4)
(3x + 2)(2x + 7)
6(x + 2)(x - 7)
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Multiple Choice
Factor by grouping:
4p³ + 8p² + 3p + 6
(2p² + 3)(p + 2)
(2p² + 6)(p + 4)
(4p² + 3)(p + 2)
(4p² + 8p)(3p + 6)
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Always factor out the GCF first (if there is one)
Take the factors of a and c that ADD to make b
Rewrite b as a sum or difference (depending on the signs) of those factors.
Factor by Grouping method:
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Factor by Grouping
A polynomial can be factored by grouping only if these conditions exist:
There are 4 or more terms
Terms have common factors that can be grouped together
There are two common factors that are identical or additive inverses of each other
ax + bx + ay + by = (ax + bx) + (ay + by)
= x(a + b) + y(a + b)
= (x + y)(a + b)
Some text here about the topic of discussion
19
Multiple Choice
Factor
3v2 + 3v - 7v - 7
(3v-7)(v+1)
3(v-7)(v-1)
(3v+1)(v-9)
(3v+1)(v-10)
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Multiple Choice
Factor by grouping.
20x3 - 25x2 + 4x - 5
(5x2 - 5)(4x + 1)
5(x2 - 1)(4x + 5)
(5x2 + 1)(4x - 5)
(5x2 + 1)(4x - 1)
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Multiple Choice
Factor:
6x2 + 2x – 21x – 7
(2x +7)(3x – 1)
(1x – 1)(6x+7)
(2x – 7)(3x+1)
(6x – 7)(1x+1)
Factor by Grouping
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