Describing Volume Formula V=Bh

Multiple Choice

BELL-RINGER QUESTION

The two lines graphed on the coordinate grid represent a system of equations. 

Which ordered pair is the solution of the system of equations?

• (5, 4)

• (0, -5)

• (8, 3)

• (4, 5)

Math Response

PARTNER PRACTICE

1. Write the algebraic expression to determine the volume of the given solid and measurements.

NOTE: What solid is displayed?

Type answer here

Correct Answer: 4^3

Deg^°

Rad

Math Response

PARTNER PRACTICE

2. Write the algebraic expression to determine the volume of the given solid and measurements.

NOTE: What solid is displayed?

Type answer here

Correct Answer: \left(\frac{1}{2}\times4\times2\right)\times6

Deg^°

Rad

Math Response

PARTNER PRACTICE

3. Write the algebraic expression to determine the volume of the given solid and measurements.

NOTE: What solid is displayed?

Type answer here

Correct Answer: \frac{1}{3}\times\left(6\right)^2\times4

Deg^°

Rad

Math Response

PARTNER PRACTICE

4. Write the algebraic expression to determine the volume of the given solid and measurements.

NOTE: What solid is displayed?

Type answer here

Correct Answer: \pi\times\left(4\right)^2\times10

Deg^°

Rad

Math Response

PARTNER PRACTICE

5. Write the algebraic expression to determine the volume of the given solid and measurements.

NOTE: What solid is displayed?

Type answer here

Correct Answer: \frac{1}{3}\times\pi\times\left(5\right)^2\times12

Deg^°

Rad

Math Response

PARTNER PRACTICE

6. Write the algebraic expression to determine the volume of the given solid and measurements.

NOTE: What solid is displayed?

Type answer here

Correct Answer: \frac{4}{3}\times\pi\times\left(3\right)^3

Deg^°

Rad

Multiple Choice

EXIT TICKET 03/31 - TEK 8.6A

When lightning strikes sand, pieces of glass in the shape of a cylinders for formed called fulgurite.  A student found a fulgurite with a height of 21 inches and a diameter of 6 inches.  Which equation can be used to find V, the volume of the fulgurite in cubic inches?

• V= π(6)² x (21)

• V= π(3)² x (21)

• V= π(6) x (21)

• V= π(3) x (21)