Directed Line Segment

​Topic Test 1 & 2 Review Part 3 Lessons

Multiple Choice

Find the point that is 2/5 of the distance from D to C.

$$\left(x,y\right)=\left(\frac{mx_1+nx_2}{m+n},\frac{my_1+ny_2}{m+n}\right)$$  ****THIS QUESTION IS NOT ON THE PACKET. DRAW THE GRAPH AND SOLVE THE PROBLEM ON THE BACK OF THE PACKET*****

• (-1, 2)

• (0,0)

Fill in the Blanks

What is the y-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:3?

$\left(x,y\right)=\left(\frac{mx_1+nx_2}{m+n},\frac{my_1+ny_2}{m+n}\right)$   ****THIS QUESTION IS NOT ON THE PACKET. DRAW THE GRAPH AND SOLVE THE PROBLEM ON THE BACK OF THE PACKET*****

Multiple Choice

If point P is 9/11  of the distance from M to N, what ratio does the point P partition the directed line segment from M to N into?

****THIS QUESTION IS NOT ON THE PACKET. DRAW THE GRAPH AND SOLVE THE PROBLEM ON THE BACK OF THE PACKET*****

• 9:2

• 9:9

• 9:11

• 9:13

Multiple Choice

Which type of triangle has vertices at the points 𝑅(2,1), 𝑆 (2,5), and 𝑇(4,1)? #11

• A. right

• B. acute

• C. isosceles

• D. equilateral

Fill in the Blanks

What is the PERIMETER of rectangle BCDE? #18

Fill in the Blanks

What is the area of rectangle EFGH? #19

Fill in the Blanks

On the set of axes below, triangle KLM has vertices

whose coordinates are K(−6, −2), L(6, −4), and

M(2, 6). What is the perimeter of triangle KLM? Round

your answer to the nearest tenth. #16

Home

Open in new tab

Copy link

Multiple Choice

Determine the Midpoint and the Length of the graphed Line Segment: #34

• $$M\left(\frac{3}{2},-\frac{5}{2}\right)$$ and $$d=\sqrt{74}$$

• $$M\left(\frac{7}{2},-\frac{5}{2}\right)$$ and $$d=\sqrt{24}$$

• $$M\left(-2,0\right)$$ and $$d=\sqrt{74}$$

Multiple Choice

Q is the midpoint of PR. PQ = 6x – 7 and QR = 5x + 1. Find the length of PR. #30

• 8
• 16
• 41
• 82

Home

Open in new tab

Copy link

Home

Open in new tab

Copy link

Multiple Choice

When copying line segment AB using a straight edge and a compass, the compass should be used to: #1

• Draw an arc above point A

• Measure the length of segment AB

• Draw an arc between point A and point B

• Measure half the length of line segment AB

Reorder

Reorder the following. #31

• Use a straight edge to draw a line segment longer than PQ. Label the point C on the new segment.

• Set your compass at the length of PQ.

• Place your compass at C. Mark point D on the new segment. $$\overline{CD}\cong\overline{PQ}$$  

1

2

3

• 1
• 2
• 3

Home

Open in new tab

Copy link

Multiple Choice

The drawing shows a compass and straight edge construction of...what? #13

• the bisector of a given angle

• a perpendicular to a given line at a point on the line

• a perpendicular to a given line from a point NOT on the line

• an angle congruent to a given angle

Multiple Choice

What will be the result of Ruben’s construction? #14

• Ruben constructs a segment perpendicular to AC.

• Ruben constructs the bisector of AC.

• Ruben constructs an angle congruent to ∠B.

• Ruben constructs the bisector of ∠B.

Multiple Choice

Find the value of x.

*****NOT ON THE PACKET.******

• 41

• 45

• 31

• 98

Multiple Choice

The Contrapositive of the statement: If p, then q. #15

• If p, then q.

• If q, then p.

• If ~ (not) p, then ~ (not) q.

• If ~ (not) q, then ~ (not) p.

Multiple Choice

Given, "If I have a Siberian Husky, then I have a dog." Identify the converse. #6

• If I do not have a Siberian Husky, then I do not have a dog.
• If I have a dog, then I have a Siberian Husky.
• If I do not have a dog, then I do not have a Siberian Husky.
• If I do not have a Siberian Husky, then I have a dog. 

Multiple Choice

Given, "If I have a Siberian Husky, then I have a dog." Identify the inverse. #7

• If I do not have a Siberian Husky, then I do not have a dog.
• If I have a dog, then I have a Siberian Husky.
• If I do not have a dog, then I do not have a Siberian Husky.
• If I do not have a Siberian Husky, then I have a dog. 

Weighted Average - Formula, Calculations, Examples

You can open this webpage in a new tab.

Copy link

Open in new tab

Home

Open in new tab

Copy link

Home

Open in new tab

Copy link

Multiple Choice

What is the justification?

REMEMBER, REMEMBER, REMEMBER #5

• Definition of Supplementary Angles

• Vertical Angles Theorem

• Definition of an Angle Bisector

• Angle Addition Postulate