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Trigonometry Sohcahtoa

Trigonometry Sohcahtoa

Assessment

Presentation

Mathematics

9th Grade

Hard

Created by

Joseph Anderson

FREE Resource

9 Slides • 13 Questions

1

Learning Sohcahtoa

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2

Multiple Choice

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What is the length of the hypotenuse in this triangle?

1

124

2

141

3

188

4

There is no hypotenuse

3

Multiple Choice

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With regard to the reference angle shown, which side is the OPPOSITE side?

1

x

2

y

3

w

4

Multiple Choice

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With regard to  θ\theta  which side is the adjacent in this RAT?

1

q

2

m

3

p

5

Multiple Choice

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If  5656^{\circ}  is the reference angle, which is the adjacent side?



1

u

2

g

3

k

6

Multiple Choice

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If  34°34\degree is the reference angle, which is the adjacent side?   

1

u

2

g

3

k

7

Multiple Choice

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Which is the hypotenuse in this triangle?

1

c

2

a

3

b

4

There is no hypotenuse

8

Multiple Choice

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With   64°64\degree   as the reference angle, which is the opposite side?

1

AB

2

BC

3

AC

9

Multiple Choice

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What is the value of the unknown angle at the corner labelled B?

1

26°26\degree

2

36°36\degree

3

64°64\degree

4

90°90\degree

10

The trigonometric ratios

There are three trigonometric ratios. They are ONLY used with Right Angled Triangles (RATs)

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11

Sine ratio

The sine ratio is abbreviated as sin
For a given reference angle, the sine ratio is the ratio


 oppositehypotenuse\frac{\text{opposite}}{\text{hypotenuse}}  

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12

Cosine ratio

The cosine ratio is abbreviated as cos. For a given reference angle, the cosine ratio is:

 adjacenthypotenuse\frac{\text{adjacent}}{\text{hypotenuse}}  

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13

 Tangent ratio

The tangent ratio is abbreviated as tan. For a given reference angle, the tangent ratio is:

 oppositeadjacent\frac{\text{opposite}}{\text{adjacent}}  

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14

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15

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label triangle first!

16

(i) Sine



 sin(β)=opphyp\sin\left(\beta\right)=\frac{\text{opp}}{\text{hyp}}  

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17

Solution

Start with the sine ratio.

 sin(β)=opphyp\sin\left(\beta\right)=\frac{\text{opp}}{\text{hyp}}  

 sin(β)=bc\sin\left(\beta\right)=\frac{\text{}b}{c}  

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18

Multiple Choice

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What is an expression for 
cos(β)\cos\left(\beta\right)  ?

1

ca\frac{c}{a}  

2

ac\frac{a}{c}  

3

bc\frac{b}{c}  

4

cb\frac{c}{b}  

5

ab\frac{a}{b}  

19

Multiple Choice

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What is an expression for
tan(β)\tan\left(\beta\right)  ?

1

ac\frac{a}{c}  

2

bc\frac{b}{c}  

3

ba\frac{b}{a}  

4

ab\frac{a}{b}  

5

ca\frac{c}{a}  

20

Multiple Choice

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What is a correct trigonometric ratio for the triangle shown?

1

tan(γ)=ac\tan\left(\gamma\right)=\frac{a}{c}

2

sin(γ)=ca\sin\left(\gamma\right)=\frac{c}{a}

3

cos(γ)=cb\cos\left(\gamma\right)=\frac{c}{b}

4

sin(γ)=cb\sin\left(\gamma\right)=\frac{c}{b}

21

Multiple Choice

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Which equation would be correct for the right angled triangle shown?

1

tan(35°)=t17\tan\left(35\degree\right)=\frac{t}{17}

2

sin(35°)=t17\sin\left(35\degree\right)=\frac{t}{17}

3

cos(35°)=17t\cos\left(35\degree\right)=\frac{17}{t}

4

sin(35°)=17t\sin\left(35\degree\right)=\frac{17}{t}

22

Multiple Choice

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Which equation would be true for the triangle shown?

1

tan(θ)=2031\tan\left(\theta\right)=\frac{20}{31}

2

sin(θ)=2031\sin\left(\theta\right)=\frac{20}{31}

3

cos(θ)=2031\cos\left(\theta\right)=\frac{20}{31}

4

tan(θ)=3120\tan\left(\theta\right)=\frac{31}{20}

5

sin(θ)=3121\sin\left(\theta\right)=\frac{31}{21}

Learning Sohcahtoa

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