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Diamond Factoring

Diamond Factoring

Assessment

Presentation

Mathematics

10th Grade

Hard

Created by

Joseph Anderson

FREE Resource

11 Slides • 9 Questions

1

Factoring Review

Learning Target: I can factor quadratic expressions

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2

Poll

Do you remember how to factor from first semester?

I don't remember factoring at all!

I might remember some steps

I feel confident in my ability to factor

3

Factoring Steps


 3x2+22x163x^2+22x-16  

Use an area model and diamond problem to factor quadratics

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4

Step 1

Place your x2 term and your constant diagonal from one another.

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5

Multiple Choice

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What do we do with those two values?

1

Add them and put them in the bottom of the diamond

2

Multiply them and put them in the bottom of the diamond

3

Multiply them and put them in the top of the diamond

4

Add them and put them in the top of the diamond

6

Step 2

Multiply your x2 term and your constant. Place in the TOP of your diamond problem.

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7

Open Ended

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What goes in the bottom of your diamond problem?

3x2+22x163x^2+22x-16  

8

Step 3

Place your x term in the bottom of your diamond.

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9

Step 4

Solve your diamond problem. Make a list of factors if it is helpful.

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10

Multiple Choice

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Which set of numbers should we use in our diamond problem?

1

-1 & 48

2

-2 & 24

3

-3 & 16

4

-4 & 12

5

-6 & 8

11

Step 5

Place the values into the missing spaces in your area model.

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12

Fill in the Blank

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Step 6 is to find the outside, and step 7 is to write your answer as a product. In the blank below, write your answer as a product. (use parenthesis, all lowercase letters, and no spaces)

13

Step 6 & 7

Find the outsides of your area model. Then write you answer as a product.

 (3x2)(x+8)\left(3x-2\right)\left(x+8\right)  




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14

Multiple Choice

Factor completely: x2-6x+8
1
(x-2)(x-4)
2
(x-1)(x-8)
3
(x+2)(x+4)
4
(x+1)(x+8)

15

Multiple Choice

Factor completely:
 3x² + 5x - 12
1
(3x + 4)(x-3)
2
(3x - 4)(x + 3)
3
(3x + 3)(x -4)
4
(3x - 3)(x + 4)

16

When terms are missing

  • use patterns like difference of squares

  • factor out a gcf

  • add a zero in for the missing term

17

Multiple Choice

Factor:x- 25
1
( x + 5 ) ( x - 5 ) 
2
( x - 5 ) ( x - 5 ) 
3
( x + 5 ) ( x + 5 ) 
4
Prime

18

Greatest Common Factor (GCF)

  • When all factors of an expression share a common factor, we can factor it out

  • Look at this expression:  4x2+10x64x^2+10x-6  

  • Each term has a factor of 2

19

Greatest Common Factor (GCF)

  • Each term has a 2 in it    4x2+10x64x^2+10x-6  

  • Factor a 2 out     2(2x2+5x3)2\left(2x^2+5x-3\right)  

  • Now use your box and diamond method to factor the terms in the parenthesis.

  • At the end, make sure to include the 2 in your answer

  •  2(2x1)(x+3)2\left(2x-1\right)\left(x+3\right)  

20

Multiple Choice

Factor completely:
2x26x1082x^2-6x-108  

1

(x9)(x+6)\left(x-9\right)\left(x+6\right)  

2

2(x+9)(x6)2\left(x+9\right)\left(x-6\right)  

3

2(x9)(x+6)2\left(x-9\right)\left(x+6\right)  

4

(x+9)(x6)\left(x+9\right)\left(x-6\right)  

Factoring Review

Learning Target: I can factor quadratic expressions

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