Factoring Quadratics with Asterisk

4.4: Factoring Quadratics: Special Cases​

EQ:  How can you factor Special Quadratic Trinomials using the algebraic patterns of perfect square trinomials, and difference of squares? ​

Multiple Choice

  $$\left(x+3\right)^2$$  

• $$x^2+6x+9$$  

• $$x^2+9$$  

• $$x^2+3x+9$$  

• $$x^2+6x+6$$  

Multiple Choice

$$\left(5x-3\right)^2$$  

• $$25x^2-9$$  

• $$5x^2-15x-9$$  

• $$25x^2-30x+9$$  

• $$5x^2+30x-3$$  

Multiple Choice

$$\left(x+7\right)\left(x-7\right)$$  

• $$2x-14$$  

• $$x^2-49$$  

• $$2x^2-14$$  

• $$x^2+49$$  

Multiple Choice

$$\left(2x+4\right)\left(2x-4\right)$$  

• $$2x^2-4$$  

• $$4x^2-8$$  

• $$4x^2-4$$  

• $$4x^2-16$$  

Multiple Choice

Factor

x² + 24x + 144

• (x + 12)²

• (x + 9)²

• (x + 15)²

• (x + 13)²

Multiple Choice

Factor

4x² + 36x + 81

• 2(2x + 9)²

• (2x + 9)²

• (2x + 9)(2x - 9)

• (2x - 9)²

Multiple Choice

Factor Completely:

2n² + 20n + 50

• (4n + 5)(2n - 5)

• 2(n + 25)(n + 1)

• 2(n - 5)²

• 2(n + 5)²

Multiple Choice

Factor

x² - 30x + 225

• (x - 15)²

• (x + 15)²

• (x + 25)²

• (x - 25)²

Multiple Choice

Factor

64x² - 16x + 1

• (8x + 1) (8x - 1)

• 4(8x - 1)²

• (8x + 1)²

• (8x - 1)²

Multiple Choice

Factor Completely

5x² - 20x + 20

• (5x + 2)²

• 5(x - 4)²

• 5(x - 2)²

• 5(x + 2)²

Multiple Choice

Factor

x² - 16

• (x - 4) (x + 4)

• (x - 4)²

• (x - 8) (x + 8)

• (x - 4) (x - 4)

Multiple Choice

Factor

4x² - 9

• 2(2x - 3)(2x + 3)

• (2x - 3)(2x + 3)

• (2x - 3)²

• (2x + 3)²

Multiple Choice

Factor

36x² - 25

• (6x - 5)(6x + 5)

• (9x + 5)(4x - 5)

• (6x + 5)(6x + 5)

• (36x - 1)(x + 25)

Multiple Choice

Factor Completely

3x² - 27

• 3(x + 9)²

• 3(x + 9) (x - 1)

• 3(x - 3)²

• 3(x + 3)(x - 3)

Multiple Choice

Factor Completely

2x² - 72

• 2(x - 6)²

• 2(x + 36)²

• 2(x - 6)(x + 6)

• (x - 6)²

Multiple Choice

Factor Completely

4x² - 100

• 4(x + 5)²

• 4(x - 5)²

• 4(x + 5) (x - 5)

• (2x + 25) (2x - 25)