
Pre Algebra Review Solving Equations
Presentation
•
Mathematics
•
9th Grade
•
Hard
Joseph Anderson
FREE Resource
30 Slides • 18 Questions
1
&
Intro: Systems
2
3
4
Multiple Choice
3x - 5 = 10
What is the first step to solving this equation?
add 5
subtract 5
divide 5
multiply 5
5
Multiple Choice
3x = 15
What is the next step to solving this equation?
add 3
subtract 3
divide 3
multiply 3
6
Multiple Choice
5x=5
What is the first step to solving this equation?
add 5
subtract 5
divide 5
multiply 5
7
Multiple Choice
5x=5
x=1
x=25
x=0
x=10
8
Multiple Choice
2x=4
What is the first step to solving this equation?
add 2
subtract 2
divide 2
multiply 2
9
Multiple Choice
2x=4
x=2
x=6
x=8
x=-2
10
Multiple Choice
4x=16
What is the first step to solving this equation?
add 4
subtract 4
divide 4
multiply 4
11
Multiple Choice
4x=16
x=12
x=20
x=64
x=4
12
Dropdown
The first step to solve this problem is to
13
Dropdown
The first step to solve this equation is to
14
Fill in the Blanks
2x=1
Type answer...
15
Fill in the Blanks
5x = 30
Type answer...
16
Fill in the Blanks
x + 2 = 10
Type answer...
17
using:
Graphing/Substitution/Elimination
18
Which method you use depends on what form(s) your equations are in.
19
This method works best with equations in slope-intercept form, when you have graph paper or a graphing calculator.
20
It is simply two or more equations.
On the graph is ...
y = 2x + 1
y = -x + 7
To solve a system, you find the point where the lines intersect.
On this graph it is (2,5)
21
Plug in to each equation.
y = 2x + 1
5 = 2(2) + 1
5 = 4 + 1
5 = 5
y = -x + 7
5 = -2 + 7
5 = 5
22
23
Multiple Choice
What is the solution to this system of equations?
(-1,4)
(4,1)
(4,-1)
(1,4)
24
Find the answer at the point where the lines cross.
25
As you can see in the graph, sometimes where the lines cross is not at a perfect point.
So other methods are needed to be get an accurate answer.
26
There is more than one way to solve systems.
The one I just showed was graphically.
Now we are going to focus on the method of SUBSTITUTION
27
Use this method when one or both equations are or are easily solved for one of the variables.
28
This video shows the situation where y is by itself in both equations.
29
Step 1: One of your equations is already set up as x=_____ or y=_____.
In fact, they both are.
Step 2: Substitute y = -4x + 8 into the other equation for y.
30
Step 2 continued: solve for x.
Step 3: Substitute x = 3 into one of your original equations and solve for y.
Step 4: Write your answer as (3, -4).
31
Since BOTH equal y ... we can substitute one of the expressions for y.
y = x - 3
y = -x + 5
Substitute
x - 3 = -x + 5
32
You can see the work to the right.
We get x by itself.
BUT we are not done.
The answer is where the lines cross.
So we need a coordinate. (x,y)
We now have the x.
We need to find the y.
33
Our answer from the substitution...
x = 4
We can pick EITHER equation, plug in the x and find the y.
Let's use: y = x - 3
(you can see the work to the right)
Answer is: (4,1)
34
Since BOTH equal y ... we can substitute one of the expressions for y.
y = -x - 1
y = -5x - 17
Substitute
-x - 1 = -5x - 17
35
36
Multiple Choice
Solve the following system:
y=−x−1
y=−5x−17
(−4,3)
(4, 3)
(3, 4)
(3, −4)
37
Since BOTH equal y ... we can substitute one of the expressions for y.
y = x - 1
y = 2x + 2
Substitute
x - 1 = 2x + 2
38
39
Multiple Choice
Solve the following system:
y=x−1
y=2x+2
(−4,−3)
(4, 3)
(3, 4)
(−3, −4)
40
This video shows the situation where y is by itself in just one equation.
41
Since y is by itself in ONLY ONE equation ... we must substitute what y equals into the other equation in place of the y.
y = 4x - 11
Substitute
42
43
Multiple Choice
Solve the following system:
y=4x−11
−4x+3y=−1
(4,−5)
(−4, 5)
(4,5)
(5,−4)
(−5,4)
44
1) Solve for x
2) Plug in the x and solve for y
ANSWER (4,3)
45
Multiple Choice
Solve the following system:
y=x−1
2x−3y=−1
(−4,3)
(4,3)
(−4,−3)
(4,−3)
46
47
Use this method when your equations are or are easily written in the same format. This is easiest when one set of terms "matches".
48
This video shows the Elimination Method.
&
Intro: Systems
Show answer
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