Unit 3 Force and Motion Test Review

A train travels 200 km between two cities. It left at 2 pm and arrived at 4 pm. What was the trains average speed?S= d/t

• 10 km/h
• 100 km/h
• 400 km/h
• 200 km/h

The velocity of a car doubles over a certain amount of time. What additional information would you need to determine the acceleration of the car?A= Velocity^final-Velocity^initial/ Time  

• The distance
• The starting velocity
• The average speed
• The route traveled

Tags

NGSS.HS-PS2-1

Mr. Michels says that the swings at the amusement park (see picture) have a constant velocity. Which of the following demonstrates why he is wrong?

• The speed is constant
• The swings change direction
• Mr. Michels was correct

Tags

NGSS.MS-PS3-1

NGSS.MS-PS3-5

Which is the correct way to calculate acceleration

• Work divided by time
• Mass times acceleration
• Distance divided by time
• Change in velocity divided by the change in time

Tags

NGSS.HS-PS2-1

What is the force necessary to stop a car that has a mass of 5 kg and an acceleration of 10m/s.F= m x a

• 5 N
• 50N
• 15N
• 500 N

Tags

NGSS.HS-PS2-1

A boy slides down a slide. What is the force that brings the boy to a stop?Hint: the force that opposes motion

• Gravity
• Friction
• Static Electricity
• Motion

A student is walking with his lunch tray and he stops short. His fork continues to move after the boy has stopped and falls off the tray. Why does this happen?

• The boy pushed the fork over
• The fork has friction
• The fork has gravity
• The fork has inertia

Two forces are acting on the rope. What is the net force of the rope. (look at the picture)  

• 0 N
• 2 N to the right
• 2N to the left
• 22 N to the right

Tags

NGSS.MS-PS2-2

Two kids push forward with their hands while on skates. Which one of Newton's laws explains why even though they apply a force forwards they move backwards. (Look at the picture) 

• Newton's first law
• Newton's second law
• Newton's third law
• Newton's fourth law

Tags

NGSS.MS-PS2-1

A student applied 100 N to push a wheel borrow 5 meters. How much work has been done? W=f x d

• 20 watts
• 105 j
• 20 j
• 500 j