Solve by Factoring

In the equation
 (x + 2)(x - 3) = 0, the binomials are called...?

• Factors
• Products
• Multiples
• Zeros

Tags

CCSS.HSA.APR.B.2

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

What are the values of x when y = 0?

• { -3, 1 }
• { -2 }
• { -3, -1 }
• { 1, 3 }

Tags

CCSS.HSF-IF.C.7A

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(2x - 1)(x + 4) = 0

• { 1/2, -4 }
•  { 1/2, 4 }
• { 2, -4 }
• { -2, 4 }

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }
• { -2, -3 }
• { 2, 3 }
• { -2, 3 }

Tags

CCSS.HSA-REI.B.4B

Factor x²-16

• (x+4)²

• (x-4)²

• (x-16)(x+16)

• (x-4)(x+4)

Tags

CCSS.HSA.APR.C.4

Factor Completely:

x² - 36

• (x + 9)(x - 4)

• (x - 6)(x - 6)

• (x - 9)(x + 4)

• (x + 6)(x - 6)

Tags

CCSS.HSA.APR.C.4

Factor:
p² - 14p

• p(1 - 14)
• 2p(p - 7)
• p²(1-14)
• p(p - 14)

Solve for the values of x:
(2x + 5)(5x - 2) = 0

• { -5/2, -2/5 }
• { -5/2, 2/5 }
• { 5/2, 2/5 }
• { 5/2, -2/5 }

Tags

CCSS.HSA-REI.B.4B