Solving Quadratics

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

If the discriminant equals 0, then the quadratic has:

• 1 Real Solution
• 2 Real Solutions
• Half a Solution
• No Real Solution

What is the discriminant?

• b²-4ac
• b²/2a
• 4ac
• b²±4ac

• A
• B
• C
• D

• A
• B
• C
• D

b² - 4ac would equal: y = 2x² -x -3

• 25
• -23
• -25
• 0

Solve
a² + 2a - 24 = 0

• a = -6, 4
• a = 6, -4
• a = 12, -2
• a = 8, -3

Solve
4m² - 100 = 0

• m=25, -25
• m=96
• m=5, -5
• m=-96

Convert x²-6x+9 to factored form and identify the solution.

• (x-3)(x-3); x=3
• (x+3)(x+3); x=-3
• (x+4)(x+2); x=-4, -2
• Not factorable

Determine the values of
a, b, and c for
the quadratic equation: 
4x² – 8x = 3

• a = 4, b = -8, c = 3
• a = 4, b =-8, c =-3
• a = 4, b = 8, c = 3
• a = 4, b = 8, c = -3