Unit 3 Regents Questions

Given 2x + ax – 7 > –12, determine the largest integer value of a when x = –1.

• a= 3
• a= 2
• a= - 3
• a = - 2

Solve the inequality below to determine and state the smallest possible value for x in the solution set.    
3(x + 3)  ≤ 5x – 3

• x = 5
• x = 6
• x = 7
• x = 4

The inequality below is equivalent to...
7 - ⅔x < x - 8

• (1) x > 9 
• (3) x < 9
• (2) x > -3/5
• (4) x < -3/5

Connor wants to attend the town carnival.  The price of admission to the carnival is $4.50, and each ride costs an additional 79 cents.  If he can spend at most $16.00 at the carnival, which inequality can be used to solve for r, the number of rides Connor can go on, and what is the maximum number of rides he can go on?

• (1) 0.79 + 4.50r ≤ 16.00; 3 rides 
• (3) 4.50 + 0.79r ≤ 16.00; 14 rides
• (2) 0.79 + 4.50r ≤ 16.00; 4 rides
• (4) 4.50 + 0.79r ≤ 16.00; 15 rides

Natasha is planning a school celebration and wants to have live music and food for everyone who attends. She has found a band that will charge her $750 and a caterer who will provide snacks and drinks for $2.25 per person.  If her goal is to keep the average cost per person between $2.75 and $3.25, how many people, p, must attend?                       

• (1) 225 < p < 325
• (3) 500 < p < 1000
• (2) 325 < p < 750 
• (4) 750 < p < 1500

Determine the smallest integer that makes –3x + 7 – 5x < 15 true.

• 1
• -1
• 0
• 2

The cost of a pack of chewing gum in a vending machine is $0.75.  The cost of a bottle of juice in the same machine is $1.25. Julia has $22.00 to spend on chewing gum and bottles of juice for her team and she must buy seven packs of chewing gum.  If b represents the number of bottles of juice, which inequality represents the maximum number of bottles she can buy?

• (1) 0.75b + 1.25(7) ≥ 22
• (3) 0.75(7) + 1.25b ≥ 22
• (2) 0.75b + 1.25(7) ≤ 22
• (4) 0.75(7) + 1.25b ≤ 22

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.CED.A.2

CCSS.HSA.CED.A.3

Solve for x algebraically.    
7x – 3(4x – 8) ≤ 6x + 12 – 9x 

• X > 6 (7, 8, 9)
• X < 6 (3, 4, 5)
• X ≥ 6 (6, 7, 8)
• X ≤ 6 (4, 5, 6)

When 3x + 2 ≤ 5(x – 4) is solved for x, the solution is

• (1) X ≤ 3
• (3) X ≤ -11
• (2) X ≥ 3
• (4) X ≥ 11

What is the solution to 
2h + 8 > 3h – 6 ?

• (1) h < 14
• (3) h > 14
• (2) h < 14/5 
• (4) h > 14/5