Search Header Logo

Function Transformations

Mathematics

9th - 12th Grade

CCSS covered

Used 32+ times

Function Transformations
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

The graph shows the function f(x)=x2 in blue and another function g(x) in red.  Which could be the equation for g(x)?

A.  g(x)=3x2
B.  g(x)=1/3x2
C.  g(x) = x2 - 3
D.  g(x) = (x-3)2

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

The graph shows the function f(x)=x3 in blue and another function g(x) in red.  Which could be the equation for g(x)?

A.  g(x) = -x3
B.  g(x) = x3 - 1
C.  g(x) = (x + 1)3
D.  g(x) = (x - 1)3

Tags

CCSS.HSF.BF.B.3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

The graph shows the function f(x)=x2 in blue and another function g(x) in red.  Which could be the equation for g(x)?

A.  g(x) = 2x2
B.  g(x) = 1/2x2
C.  g(x) = x2 + 2
D.  g(x) = (x + 2)2

Tags

CCSS.HSF.BF.B.3

CCSS.HSA.CED.A.2

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

The graph shows the function f(x)=x2 in blue and another function g(x) in red.  Which could be the equation for g(x)?

A.  y = 1/2(x - 3)2
B.  y = 1/2(x + 3)2
C.  y = 2(x - 3)2
D.  y = 2(x + 3)2

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSA.REI.D.11

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

The graph shows the function f(x)=x3 in blue and another function g(x) in red.  Which could be the equation for g(x)?

A.  y = x3
B.  y = -0.1x3
C.  y = -5x3
D.  y = -10x3

Tags

CCSS.HSF.BF.B.3

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?