Math 2 Quadratics Review

The function h(x) is defined as h(x)=x². If g(x) is the function h(x) translated up 4 and right 7, what is the formula for g(x) in vertex form?

• g(x)=(x+7)²+4
• g(x)=(x-4)²+7
• g(x)=(x-7)²+4
• g(x)=(x+4)²-7

The function h(x) is defined as h(x)=x². If g(x) is the function h(x) translated up 4 and right 7, what is the formula for g(x) in standard form?

• g(x)=x²-53
• g(x)=x²-14x+53
• g(x)=x²-7x+4
• g(x)=12x+53

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. How high is the object after 1 second?

• 143 meters
• 49 meters
• 238 meters
• 110 meters

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. How tall is the platform?

• 143 meters
• 49 meters
• 238 meters
• 110 meters

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. When does the object hit the ground?

• about 7.3 seconds
• about 3.4 seconds
• about 7.8 seconds
• 8 seconds

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. What is the maximum height of the object?

• exactly 143 meters
• about 49 meters
• about 238 meters
• exactly 110 meters

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. When does it reach its maximum height?

• about 7.3 seconds
• about 3.4 seconds
• about 7.8 seconds 
• 8 seconds

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. When is the object 20 meters high?

• about 7.13 seconds
• about 3.4 seconds
• about 7.8 seconds
• about 8 seconds

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. What is the domain of the object's motion?

• -∞<x<∞
• 0≤x<∞
• 0≤x≤7.29
• -∞≤x≤∞

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. What is the range of the object's motion?

• -∞<y<∞
• 0≤y<∞
• 0≤y≤238
• -∞<y<238