Linear & Quadratic Systems

Which of the following equations could be used to solve:
y = x² + 3x - 5
y = x + 3

• x² - 3x + 5 = x - 3
• x² + 3x - 5 = x + 3
• x² + 3x - 5 + x + 3 = 0
• x² + 3x - 5 = 0

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.C.7

CCSS.HSA.REI.D.11

What are the solutions to the system:
y = x² + 3x - 5
y = x + 3

• (-4, 2) and (-1, 5)
• (-4, -1) and (2, 5)
• (2, -1 and (-4, 5)
• (-4, 1) and (2, -1)

Tags

CCSS.HSA.REI.C.7

Find the solution:
y = x² - 4x + 6
y = x + 2

• (3, 1) and (6, 4)
• (-1, 1) and (4, 2)
• (1, 3) and (4, 6)
• (1, 4) and (3, 6)

Tags

CCSS.HSA.REI.C.7

3.

• R
• W

4.

• Y
• B

• A
• B
• C
• D

Tags

CCSS.HSA.REI.C.7