Unit 8 Solving Quadratics

Find the zeros of this quadratic.

• b=4/5, b=3
• b=4, b=-3
• b=1/5, b=3
• b=4/5, b=-3

Determine the values of
a, b, and c for
the quadratic equation: 
4x² – 8x = 3

• a = 4, b = -8, c = 3
• a = 4, b =-8, c =-3
• a = 4, b = 8, c = 3
• a = 4, b = 8, c = -3

9k² = 225

• 4
• 4, -4
• 25, -25
• -5, 5

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

Solve the quadratic equation by factoring
a² + 10a + 21 = 0

• ± √21
• -3 , -7
• 3 , 7
• 28 , -7

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

What is this?

• This is the speed of light formula.
• This is the quadratic formula.
• This is the zero product property.
• This is scary.

Tags

CCSS.HSA.REI.B.4

Solve using the quadratic formula:  3x² + 5x + 2 = 0  

• x = -2/3 and x = -1
• x = -3/2 and x = -1
• x = 2/3 and x = 1
• x = 2/3 and x = -1

In the equation
 (x + 2)(x - 3) = 0, the binomials are called...?

• Factors
• Products
• Multiples
• Zeros

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

What are the values of x when y = 0?

• { -3, 1 }
• { -2 }
• { -3, -1 }
• { 1, 3 }

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

CCSS.HSA.REI.D.11