Algebra 1 Quadratics 3

What's the vertex of the parabola?

• (-2,4)
• (-1,1)
• (0,0)
• (2,4)

Tags

CCSS.8.F.A.1

CCSS.8.F.B.5

If we have the equation y=ax²+bx+c, how can we can find the x-coordinate of the vertex?

• -a
• -b/a
• b/2a
• -b/2a

Tags

CCSS.HSA.REI.B.4

Which letter determines if a parabola opens up or down?

• a
• b
• c

Tags

CCSS.HSF-IF.C.7A

Solve
2x² + 17x + 21 = 0

• x= ^-21/₂, -17
• x= ²/₃, 16
• x=-7, ^-3/₂
• x=15, -³/₇

Solve
a² + 2a - 24 = 0

• a = -6, 4
• a = 6, -4
• a = 12, -2
• a = 8, -3

Factor
k²+7x+10

• (k+2)(k+5)
• (k-2)(k-5)
• (k+10)(k+4)
• (k+2)(k-5)

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

Tags

CCSS.HSA-REI.B.4B

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

Suzie solves the equation below:
x² + 4x - 12 = 2
(x - 2)(x + 6) = 2, 
by setting x -2 = 0 and x + 6 = 0. 
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property
• Yes, she factored correctly and then square rooted.
• No, she did factor correctly, but she can't use the zero product property as shown.
• No, she didn't factor correctly so the rest of her work is wrong. 

Tags

CCSS.HSA-REI.B.4B