5.4B

5.4B

5th Grade

5 Qs

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5.4B

5.4B

Assessment

Quiz

Mathematics

5th Grade

Practice Problem

Hard

CCSS
3.OA.D.8

Standards-aligned

Used 54+ times

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5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Pedro ordered 24 boxes of baseballs.  Each box contained 16 baseballs.  Pedro used 8 of these baseballs during a game.  Which equation can be used to find b, the total number of these baseballs that Pedro did NOT use during the game?

b = (24 + 16) - 8
b = (24 x 16) - 8
b = (24 - 16) / 8
b = (24 x 16) + 8

Tags

CCSS.3.OA.D.8

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

The table shows the number of hats made at a factory during three weeks in February.  The number of hats made in Week 4 is represented by n.
The total number of hats made at the factory in February was 2,148,431.  Which equation represents this situation?

2,148,431 = (562,937 + 607,822 + 492,375) + n 
2,148,431 = (562,937 + 607,822 + 492,375) n 
2,148,431 = (562,937 + 607,822 + 492,375) × n 
2,148,431 = (562,937 + 607,822 + 492,375) ÷ n 

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Mr. Anderson had 185 pieces of wood.  He sold 25 pieces of wood to his neighbor and stacked the rest of the wood into piles around his house.  Each pile of wood contained 40 pieces of wood.  Which equation can be used to find p, the number of piles of wood Mr. Anderson made?

p = (185+25)+40 
p = (185−25)−40 
p=(185+25)×40 
p=(185−25)÷40 

Tags

CCSS.3.OA.D.8

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

After spending $70 from her bank account, Keesha had a total of $126 left. Which number sentence could be used to find a, the amount of money Keesha had in her account before she spent $70?

126 – 70 = a
126 + a = 70
70 – a = 126
a – 70 = 126

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

At Lincoln Elementary School, the fifth-grade students have a total of 325 pets. Of these pets, 250 are some kind of pet other than cats. Which equation could be used to determine the number of pets that are cats, c?

325 + 250 = c
325 – 250 = c
325 × 250 = c
325 ÷ 250 = c