Solving Systems Algebraically

What is the first step in solving
3x + 2y = 8
-3x + 6y = 12

• Add the equations
• Subtract the equations
• Multiply by 4

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

-6x+5y=1
 6x+4y=-10

• (1,1)
• (-1,-1)
• (-1, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by elimination:
4x+9y=28
-4x-y=-28

• (-7,0)
• (6,0)
• (-6,0)
• (7,0)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by elimination:
4x+4y=4

3x+4y=10

• (7,-6)
• (-6,7)
• (6,7)
• (7,6)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

 -2x-9y=-25
 -4x-9y=-23

• (-1,3)
• (3,-1)
• (8,-1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations.

• (-6, 1)

• (-12, -12)

• (1, -6)

• No solution

• Infinite solutions

Tags

CCSS.8.EE.C.8B

What is the solution to this system?
2x + 3y = 4
y= 5x - 27

• (5,-2)
• (5, 2)
• (2,3)
• (3,2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Which answer has a correct first step for this system:

3x + 3y = 3

y = 3x + 5

• The variable is already isolated, so we've already solved the system.

• The variable is already isolated for y, so we substitute it in the first equation and solve for x

  3x + 3(3x + 5) = 3

• Free sha vaca doo

• The variable is already isolated for y, so we substitute it in the second equation and solve for x

  y = 3(3x + 3y) = 3

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6