Alg 2 Unit 1- Linear Functions

Find the equation of the line using the following points:

(2, 2) and (3, 4)

• y = 2x + 2
• y = -2x - 2
• y = -2x + 2
• y = 2x - 2

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

Find the equation of the line using the following points:

(3, 4) and (0, -5)

• y = 3x + 5
• y = -3x + 4
• y = -3x + 4
• y = 3x - 5

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

Graph y = -3

• A
• B
• C
• D

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

Which of the following lines goes through the point (-3, 4) and is perpendicular to
 y = 3/2x + 6?

• y = 3/2x - 6
• y = 2/3x + 3
• y = -2/3x - 2
• y = -2/3x + 2

Tags

CCSS.HSG.GPE.B.5

Given the line 2x-3y=9, write the equation of a line parallel to it that passes through the point (4, -1)

• y = -2/3x + 5/3
• y = 2/3x - 11/3
• y = 2/3x - 4
• y = -2/3x + 9

Tags

CCSS.HSG.CO.A.1

CCSS.HSG.GPE.B.5

Rewrite
4y = 3 - 4/5x
 in standard form.

• 4x - 20y = 15
• 4x + 4y = 15
• 4x + 20y = 15
• 4x + 4y = 3

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Solve for x:
2(3x + 4) + 2 = 4 + 3x

• 2
• -2/3
• 10
• -2

Tags

CCSS.8.EE.C.7B

What would you multiply to not have any fractions?
½x+4=⅕x+7

• 2
• 5
• 10
• 20

Tags

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

CCSS.HSA.REI.B.3

The least common denominator of 8 would be used in what equation?

• ¼x+2=½x-5
• ¾x+4=⅛x-8
• ¾x+5=¼x-1
• ⅗x-1=⅔x+3

Tags

CCSS.HSA.APR.D.7

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

Which of these represents point-slope form of a linear equation?

• y - y₁ = m(x - x₁)
• Ax + By = C
• y = mx + b

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3