Given: m∠LAN = 30⁰ , m∠1 = 15⁰ Prove: AM bisects ∠LAN Step 1: m∠LAN = 30⁰ Step 2: m∠1 + m∠2 = m∠LAN Step 3: m∠1 + m∠2 = 30⁰ Step 4: m∠1 = 15⁰ Step 5: 15⁰ + m∠2 = 30⁰ Step 6: m∠2 = 15⁰ Step 7: m∠1 = m∠2 Step 8: ∠1 ≅ ∠2 What is the justification for Step 8?

Symmetric property of congruence

Given: m∠LAN = 30⁰ , m∠1 = 15⁰ Prove: AM bisects ∠LAN Step 1: m∠LAN = 30⁰ Step 2: m∠1 + m∠2 = m∠LAN Step 3: m∠1 + m∠2 = 30⁰ Step 4: m∠1 = 15⁰ Step 5: 15⁰ + m∠2 = 30⁰ Step 6: m∠2 = 15⁰ Step 7: m∠1 = m∠2 Step 8: ∠1 ≅ ∠2 Step 9: AM bisects ∠LAN What is the justification for Step 9?

Symmetric property of congruence

Geometric Proofs

Authored by chooi tang

Mathematics

9th - 12th Grade

CCSS covered

Used 353+ times

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23
What is the justification for Step 1's statement?

Addition property of equality

Simplifying

Subtraction property of equality

Distributive property

Tags

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23
Step 2: 7x = 21
What is the justification for Step 2's statement?

Addition property of equality

Simplifying

Subtraction property of equality

Distributive property

Tags

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23
Step 2: 7x = 21
Step 3: x = 3
What is the justification for Step 3's statement?

Addition property of equality

Multiplication property of equality

Subtraction property of equality

Division property of equality

Tags

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
What is Step 1?

AC = AB + AB

AB = BC

AB + BC = AC

AB + AB = AB + BC

Tags

CCSS.HSG.CO.C.10

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
What is Step 2?

AC = AB + AB

AB = BC

AB + BC = AC

AB + AB = AB + BC

Tags

CCSS.HSA.REI.B.3

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
Reason 3: Transitive property of equality
What is Step 3?

AC = AB + AB

AB = BC

AB + BC = AC

AB + AB = AB + BC

Tags

CCSS.HSG.SRT.B.4

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
Reason 3: Transitive property of equality
Reason 4: Subtraction property of equality
What is Step 4?

AC = AB + AB

AB = BC

AB + BC = AC

AB + AB = AB + BC

Tags

CCSS.HSG.SRT.B.4

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Geometric Proofs

Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23
What is the justification for Step 1's statement?

Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23
Step 2: 7x = 21
What is the justification for Step 2's statement?

Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23
Step 2: 7x = 21
Step 3: x = 3
What is the justification for Step 3's statement?

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
What is Step 1?

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
What is Step 2?

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
Reason 3: Transitive property of equality
What is Step 3?

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
Reason 3: Transitive property of equality
Reason 4: Subtraction property of equality
What is Step 4?

Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
What is Step 1?

Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
Reason 2: Given
What is Step 2?

Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
Reason 2: Given
Reason 3: Definition of complementary angles
What is Step 3?

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Geometric Proofs

Solve: 3x + 2 = 23 - 4xStep 1: 7x + 2 = 23 What is the justification for Step 1's statement?

Solve: 3x + 2 = 23 - 4xStep 1: 7x + 2 = 23 Step 2: 7x = 21What is the justification for Step 2's statement?

Solve: 3x + 2 = 23 - 4xStep 1: 7x + 2 = 23 Step 2: 7x = 21Step 3: x = 3What is the justification for Step 3's statement?

Given: AC = AB + ABProve: AB = BCReason 1: GivenWhat is Step 1?

Given: AC = AB + ABProve: AB = BCReason 1: GivenReason 2: Segment addition postulateWhat is Step 2?

Given: AC = AB + ABProve: AB = BCReason 1: GivenReason 2: Segment addition postulateReason 3: Transitive property of equalityWhat is Step 3?

Given: AC = AB + ABProve: AB = BCReason 1: GivenReason 2: Segment addition postulateReason 3: Transitive property of equalityReason 4: Subtraction property of equalityWhat is Step 4?

Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3Prove: ∠1 is a complement of ∠3Reason 1: GivenWhat is Step 1?

Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3Prove: ∠1 is a complement of ∠3Reason 1: GivenReason 2: GivenWhat is Step 2?

Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3Prove: ∠1 is a complement of ∠3Reason 1: GivenReason 2: GivenReason 3: Definition of complementary anglesWhat is Step 3?

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Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23
What is the justification for Step 1's statement?

Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23
Step 2: 7x = 21
What is the justification for Step 2's statement?

Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23
Step 2: 7x = 21
Step 3: x = 3
What is the justification for Step 3's statement?

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
What is Step 1?

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
What is Step 2?

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
Reason 3: Transitive property of equality
What is Step 3?

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
Reason 3: Transitive property of equality
Reason 4: Subtraction property of equality
What is Step 4?

Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
What is Step 1?

Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
Reason 2: Given
What is Step 2?

Given: ∠1 is a complement of ∠2 and ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
Reason 2: Given
Reason 3: Definition of complementary angles
What is Step 3?