Geometric Proofs

Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23 
What is the justification for Step 1's statement?

• Addition property of equality
• Simplifying
• Subtraction property of equality
• Distributive property

Tags

CCSS.HSA.REI.A.1

Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23 
Step 2: 7x = 21
What is the justification for Step 2's statement?

• Addition property of equality
• Simplifying
• Subtraction property of equality
• Distributive property

Tags

CCSS.HSA.REI.A.1

Solve: 3x + 2 = 23 - 4x
Step 1: 7x + 2 = 23 
Step 2: 7x = 21
Step 3: x = 3
What is the justification for Step 3's statement?

• Addition property of equality
• Multiplication property of equality
• Subtraction property of equality
• Division property of equality

Tags

CCSS.HSA.REI.A.1

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
What is Step 1?

• AC = AB + AB
• AB = BC
• AB + BC = AC
• AB + AB = AB + BC

Tags

CCSS.HSA.REI.A.1

CCSS.HSG.CO.C.10

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
What is Step 2?

• AC = AB + AB
• AB = BC
• AB + BC = AC
• AB + AB = AB + BC

Tags

CCSS.HSA.REI.B.3

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
Reason 3: Transitive property of equality
What is Step 3?

• AC = AB + AB
• AB = BC
• AB + BC = AC
• AB + AB = AB + BC

Tags

CCSS.HSA.REI.A.1

Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
Reason 2: Segment addition postulate
Reason 3: Transitive property of equality
Reason 4: Subtraction property of equality
What is Step 4?

• AC = AB + AB
• AB = BC
• AB + BC = AC
• AB + AB = AB + BC

Tags

CCSS.HSA.REI.A.1

Given: ∠1 is a complement of ∠2  and  ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
What is Step 1?

• ∠1 is a complement of ∠2
• m∠1 + m∠2 = 90⁰
• m∠2 = m∠3
• m∠1 + m∠3 = 90⁰

Tags

CCSS.HSG.CO.A.1

CCSS.HSG.CO.C.9

Given: ∠1 is a complement of ∠2  and  ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
Reason 2: Given
What is Step 2?

• ∠2 ≅ ∠3
• m∠1 + m∠2 = 90⁰
• m∠2 = m∠3
• m∠1 + m∠3 = 90⁰

Tags

CCSS.HSG.CO.C.9

Given: ∠1 is a complement of ∠2  and  ∠2 ≅ ∠3
Prove: ∠1 is a complement of ∠3
Reason 1: Given
Reason 2: Given
Reason 3: Definition of complementary angles
What is Step 3?

• ∠1 is a complement of ∠3
• m∠1 + m∠2 = 90⁰
• m∠2 = m∠3
• m∠1 + m∠3 = 90⁰

Tags

CCSS.HSG.CO.C.9