82 added to a number is the same as 36

• 82=36
• 82+36=x
• t+82=36
• None of the above

Tags

CCSS.6.EE.B.5

a number is added to 22 is the same as the product of 6 and a number

• 22+u
• 22+k = 6x
• 22+u=6 + x
• u+22=6

Tags

CCSS.HSA.CED.A.3

The product of 12 and a number is the same as 2 removed from a number

• 12x=x+2
• 12x=2-x
• 12-2=x-2
• 12x= x-2

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.6

CCSS.6.EE.B.7

88 is removed from 14⁄16 a number

• 88 - 14⁄16x
• 14⁄16x - 88
• 88+14⁄16
• 14⁄16 + 88

Tags

CCSS.6.EE.A.2A

a number halved is equal to 22 fewer than a number

• b⁄2 = 22-b
• 2b =22- b
• n⁄2=n-22
• None of the above

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

A​ town's population is 47,500. About 75 people move out of the town each month. Each​ month, 125 people on average move into town. A nearby town has a population of 50,250. It has no one moving in and an average of 200 people moving away every month. In about how many months will the populations of the towns be​ equal? Write an equation to model the situation. Then solve the equation and answer the question.

• 125m-75m+50,250=47,500-200m
• 75m-125m+ 50,250 = 47,500-200m
• 75m-125m+47,500 = 50,250-200m
• 125m-75m+47,500 = 50,250-200m

Tags

CCSS.8.EE.C.7B

x/9=28

• 9 times a number is 28
• A number multiplied by 9 equals 28
• A number removed from 9 is 28
• The quotient of 9 and a number is 28

Tags

CCSS.6.EE.B.7

Rayshawn and Robert are both saving money for their summer vacations. They began saving at the same time. Rayshawn started with $10.25 and adds $5.15 to his savings every month. Robert did not have a starting amount but adds $10.25 to his savings every month. Which equation could be used to determine how many months, m, it will take before Rayshawn and Robert both have saved the same amount of money?

• 5.15m + 10.25 = 10.25m
• 10.25m + 5.15 = 10.25m
• 10.25m + 10.25 = 5.15m
• 10.25m – 5.15 = 10.25m

Tags

CCSS.6.EE.A.4

CCSS.6.EE.B.6

CCSS.6.EE.B.7

CCSS.6.EE.C.9

120 more than twice a number is the same as halve a number removed from 8

• 2t+120= t⁄2-8
• 120+2t = t⁄2-8
• 2t+120 = 8-t⁄2
• Be humble...sit down

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

The 30 members of a choir are trying to raise at least $1500 to cover travel costs to a signing camp. They have already raised $600. Which inequality would you solve to find the average amount each member can raise in order to meet the goal?

• 30x + 600  ≥ 1500
• 30x + 600  ≤ 1500
• 30x  - 600  ≤ 1500
• 30x = 1500

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

CCSS.6.EE.B.8