A.P. Physics R.M. and S.H.M.

A 550 kg mass is in simple harmonic motion on a spring, solve for the displacement if the spring constant value for the spring is 98100 N/m and the restoring force is -981 N.  

• 100 m
• .01 m
• 9.62 x 10^{8 m}

What is the distance a spring will stretch if a 785 N student hangs from a spring with a constant of 1570 N/m

• 2 m
• .5 m
• 785 m

What is the equation for frequency?

• f = t/n
• f = 1/T
• f = 2 T

Tags

NGSS.HS-PS4-1

What is the frequency of a pendulum that has a period of 10 s?

• 10 Hz
• 1/1000 Hz
• .1 Hz

Tags

NGSS.HS-PS4-1

A simple harmonic oscillator takes 4.8 s to undergo five complete vibrations. What is the period (T) of 1 cycle?

• 4.8 s
• .96 s
• 9.8 s

A simple harmonic oscillator takes 4.8 s to undergo five complete vibrations. What is the frequency of 1cycle? 

• 1.04 s
• 4.8 s
• 1/4.8 s

A mass of 0.60 kg attached to a vertical spring stretches the spring 33 cm from its original equilibrium position. The acceleration of gravity is 9.81 m/s 2 . What is the spring constant?

• 17.8 N/m
• 29.7 N/m
• .178 N/m

The period of a pendulum may be decreased by

• Increasing the mass of the bob
• moving the equilibrium point
• decreasing the mass of the bob
• shortening the length of pendulum

In any system in SHM, the restoring force acting on the mass in the system is proportional to

• the displacement
• the length of the pendulum
• the mass
• the frequency

A mass attached to a spring vibrates back and forth. At the equilibrium position, the

• acceleration reaches a maximum.
• velocity reaches a maximum.
• net force reaches a maximum.
• velocity reaches zero.