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Algebra 2 7.1.3

Authored by Joseph Giorno

Mathematics

9th - 12th Grade

CCSS covered

Used 12+ times

Algebra 2          7.1.3
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

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Sketch a graph of the first two cycles of s(θ) = sin θ

Then label your graph to show the following positions of a passenger on The Screamer


The passenger gets on initially.

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Tags

CCSS.HSF-IF.C.7E

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Sketch a graph of the first two cycles of s(θ) = sin θ

Then label your graph to show the following positions of a passenger on The Screamer


The passenger reaches the bottom of the water pit.

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Tags

CCSS.HSF-IF.C.7E

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

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Sketch a graph of the first two cycles of s(θ) = sin θ

Then label your graph to show the following positions of a passenger on The Screamer


The passenger is halfway between the highest point of The Screamer and the ground level.

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4.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

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Each of the points on the graph represents the position of a rider on The Screamer. Select the correct diagram and description to match

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(a): Above ground just past the highest point; (b): Just below ground; (c): Back to the starting point.

(a): Below ground just past the highest point; (b): Just above ground; (c): Back to the starting point.

(a): Above ground just before the highest point; (b): Just below ground; (c): At the lowest point.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

While trying to measure the height of a tree, Julie noticed that a 3.5-foot post had a 4.25-foot shadow. If the tree’s shadow is 100 feet long, how tall is the tree?

≈ 82.4 feet

≈ 121.4 feet

≈ 96.8 feet

≈ 37.9 feet

Tags

CCSS.7.RP.A.3

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given that log 2 ≈ 0.3010, log 3 ≈ 0.4771 and log 5 ≈ 0.6990, calculate the following logarithms without using the log function on your calculator


log 6

≈ 0.7781

≈ 0.0144

≈ 0.6989

No solution

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given that log 2 ≈ 0.3010, log 3 ≈ 0.4771 and log 5 ≈ 0.6990, calculate the following logarithms without using the log function on your calculator


log 15

≈ 0.7781

≈ 1.1761

≈ 0.3334

No Solution

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