Attributes of Exponential/Logarithmic Functions

What is the y-intercept of the function?

• (0, -3)

• (-3, 0)

• (1, 0)

• (0, 1)

Tags

CCSS.HSA.REI.D.10

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

What is the range of the function?

• y > -4

• y < -4

• All real numbers

• y < 2

What is the equation of the vertical asymptote?

• x = -2

• y = -2

• x = 1

• y = 1

Describe the graph of f(x) = log x changed to

f(x) = 3log(x + 1) - 5

• vertical stretch by 3 and shift right 1 and 5 units down

• vertical stretch by 3 and shift left 1 and 5 units down

• vertical compress by 3 and shift right 1 and 5 units down

• vertical compress by 3 and shift left 1 and 5 units down

Tags

CCSS.HSF.BF.B.3

CCSS.HSF.IF.C.7

Tommy starts an ant farm will 100 ants. The ants increase at a rate of 4% each day. How many ants will Tommy have after 12 days?

• 160

• 61

• 144

• 105

Tags

CCSS.HSF.BF.A.1

CCSS.HSF.BF.A.2

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

CCSS.HSF.LE.B.5

What is the growth or decay rate of h(t) = 15(.45)^t

• growth rate 45%

• decay rate 45%

• growth rate 55%

• decay rate 55%

Tags

CCSS.HSA.SSE.A.1

CCSS.HSF.LE.B.5

What is the inverse function of f(x) = 10^(x+7) - 2

• f^-1(x) = log (x - 2) - 7

• f^-1(x) = log (x - 2) + 7

• f^-1(x) = log (x + 2) - 7

• f^-1(x) = log (x + 2) + 7

Ms. Reyes deposits $2500 in the bank and earns 5.49% interest monthly. Which equation can be used to determine the amount of money she has after 20 years?

• A(x) = 2500(1 + .0549/12)¹²⁽²⁰⁾

• A(x) = 2500(1 + .0549/12)⁽²⁰⁾

• A(x) = 2500(1 + .0549)⁽²⁰⁾

• A(x) = 2500(1 + .0549)¹²⁽²⁰⁾

Money is deposited into an account with interest using the formula A = Pe^rt . How many years will it take for the amount of money to double if the interest is compounded continuously at 5%?

• 13 years

• 14 years

• 1 year

• 2 year

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.SSE.A.1

CCSS.HSF.BF.A.1

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

CCSS.HSF.LE.A.4

What is the inverse function of f(x) = ln(x-9) + 5 ?

• f^-1(x) = e^(x+5) + 9

• f^-1(x) = e^(x-5) + 9

• f^-1(x) = e^(x-5) - 9

• f^-1(x) = e^(x+5) - 9