Logarithms

Solve: 9^8-x = 27^x-3

• x = 5
• x = -5
• x = 1/5
• x = -1/5

Solve: 7^-x = 49

• x = 1
• x = -1
• x = 2
• x = -2

Solve: 2^x = 4^x+1

• x = -2
• x = 2
• x = -3
• x = 3

Sovle for x:
5^{-3x - 1} = 25

• x = -1
• x = -4
• x = -3
• x = 1

Solve for x:
3^2x = 27^{x - 4}

• x = 12
• x = 4
• x = -4
• x = 1

Solve for p:
4^p+2 = 64

• p = -16/9
• p = 1
• p = 8
• p = 7/6

Solve 3³ = 3^{4x + 2}

• x = ¼
• x = -¼
• x = ½
• x = -½

To solve 36 = 6^x, re-write 36 as what base and exponent?

• 3⁶
• 6³
• 6²
• 3¹²

To solve 8 = 2^5x+7, you would need to re-write 8 as what base?

• 8
• 4
• 2
• Cannot be determined

Solve 8 = 2^5x+7

• x = ⅘
• x = ¼
• x = -⅘
• x = -¼