Circles: General Form to Standard Form

Change the following equation to standard form
x²+y²-4x+12y-8=0

• (x+2)²+(y-6)²=48
• (x-2)²+(y+6)²=48
• (x-6)²+(y-2)²=48
• (x+2)²+(y-6)²=48

Tags

CCSS.HSG.GPE.A.1

Change the following equation to standard form
x²+y²-4x+12y-8=0

• (x+2)²+(y-6)²=48
• (x-2)²+(y+6)²=48
• (x-6)²+(y-2)²=48
• (x+2)²+(y-6)²=48

Tags

CCSS.HSG.GPE.A.1

What is the center for the circle with this equation x²+y²+4x+6y-36=0?

• (-2,5)
• (2,7)
• (-2,-7)

What is the radius of the circle with this equation x²+y²-10x+8y-23=0?

• 4
• 2
• 8

Tags

CCSS.HSG.GPE.A.1

Find the center and radius of the circle: x²+y²+14x-2=-1

• center= -7,2 radius= 3
• center= -7,1 radius= 7
• center= -4,1 radius= 5

Tags

CCSS.HSG.GPE.A.1

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)
• (-3, -2)
• (-2, -3)
• (2, 3)

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4
• 2
• 3
• 16

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the center of the circle is at...

• (-2, 3)
• (-3, 2)
• (2, -3)
• (3, -2)

Tags

CCSS.HSG.GPE.A.1

Write the standard equation of the circle with the given center and radius; center (0,0) and radius: 3

• x²+y²=3
• x²+y²=6
• x²+y²=9

Tags

CCSS.HSG.GPE.A.1

What is the equation of a circle with radius 2 and center (3, 4)?

• (x+3)² + (y+4)² = 2
• (x-3)² + (y-4)² = 2
• (x+3)² + (y+4)² = 4
• (x-3)² + (y-4)² = 4

Tags

CCSS.HSG.GPE.A.1