Solving Systems by Substitution

y = -6x + 5
-2x + y = 5

• (-3, -6)
• (-6, 3)
• (0, 5)
• (-3, 5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

5x + y = -10
y = -6x - 13

• (4, 5)
• (-3, -3)
• (3, 5)
• (-3, 5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

3y - 2x = 0
y = 4x - 1

• (0.3, 0.2)
• (-0.3, -0.2)
• (-0.3, 0.2)
• (0.3, -0.2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system by substitution.
 
5x + 4y= −14
y =  −7x  −  15 

• (-2, -1)
• (1, -2)
• (-2, 1)
• (-1, -2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve:
y = -1x - 5
4x - 8y = 4

• (-3, -2)
• (5, -7)
• (3, 9)
• (-5, 4)

Tags

TEKS.MATH.A.5C