Equations of Circles

In the equation (x + 2)² + (y - 3)²=4, the radius of the circle is...

• 4

• 2

• 3

• 16

Tags

CCSS.HSG.GPE.A.1

Write the standard equation of the circle with the given center and radius; center (0,0) and radius: 4

• x² + y² = 4

• x² + y² = 16

• x² + y² = 2

• x² + y² = 8

Tags

CCSS.HSG.GPE.A.1

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 144

• (x - 5)² + (y + 2)² = 6

• (x + 5)² + (y - 2)² = 36

• (x + 5)² + (y - 2)² = 144

Tags

CCSS.HSG.GPE.A.1

Which graph corresponds to

x²+ (y - 6)²=9

• A

• B

• C

• D

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSG.GPE.A.1

What is the center of a circle with equation (x - 4)² + y² = 5?

• (-4, 0)

• (4, 0)

• (4, 1)

• (-4, 1)

Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle?

• (x + 1)² + (y + 1)² = 3

• (x + 1)² + (y - 1)² = 3

• (x + 1)² + (y + 1)² = 9

• (x - 1)² + (y - 1)² = 9

Tags

CCSS.HSG.GPE.A.1

Find the equation of the circle with a center at (−8,3) that passes through the point (2,−5) that is located on the circle?

• (x + 8)² + (y − 3)² = 12.8

• (x + 3)² + (y − 8)² = 164

• x² + y ²= 12.8

• (x + 8)² + (y − 3)² = 164

Tags

CCSS.HSG.GPE.A.1

The endpoints of a diameter of a circle are (3,1) and (9,5). Find the equation of the circle.

• (x − 6)² + (y − 3)² = 13

• (x − 3)² + (y − 6)² = 169

• (x − 5)² + (y − 9)² = 13

• (x − 9)² + (y − 5)² = 42.25

Tags

CCSS.HSG.GPE.A.1

Which is the equation of a circle given endpoints of the diameter are (0,5) (2,3)

• (x - 1)² + (y - 4)² = 2

• (x - 1)² + (y - 4)² = 4

• (x + 1)² + (y + 4)² = 1

• (x + 1)² + (y - 4)² = 4

Tags

CCSS.HSG.GPE.A.1

Which of these points does not lie on the circle whose equation is:

(x - 2)² + (y + 3)² = 25

• (5, 1)

• (-1, 1)

• (0, 0)

• (-2, 0)

Tags

CCSS.HSA.REI.D.10

CCSS.HSG.GPE.A.1