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Quadratic Equations Part 2

Authored by Nicole Shabazz

Mathematics

8th - 12th Grade

CCSS covered

Used 3+ times

Quadratic Equations Part 2
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46 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Factor

k2+7k+10

(k+2)(k+5)

(k-2)(k-5)

(k+10)(k+4)

(k+2)(k-5)

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Factor

3v2 - 4v - 7

(3v-7)(v+1)

3(v-7)(v-1)

(3v+1)(v-9)

(3v+1)(v-10)

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Solve
x2 + 2x - 24 = 0

x = -6, x = 4
x = 6, x = -4
x = 12, x = -2
x = 8, x = -3

Tags

CCSS.HSA-REI.B.4B

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Solve (k + 1)(k − 5) = 0

(1,5)

(-1,5)

-1, 5

1, 5

Tags

CCSS.HSA-REI.B.4B

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation 
s(t) = –16t2 + 64t + 80.
What will be the object's maximum height? 

2 ft
80 ft
144 ft
64 ft

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

The function f(t) = -5t2+20t + 60 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground?

4 seconds

-2 seconds

6 seconds

9 seconds

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

For a scene in a movie, a sack of money is dropped from the roof of a 600 foot skyscraper. The height of the sack above the ground is given by h = -16t2 + 600, where t is the time in seconds. What does the y-intercept on the graph represent?

The starting height of the sack

The time it took the sack to hit the ground

The starting time the sack was dropped.

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