Unit 11 Review

Solve for the values of x:

(x + 2)(x - 3) = 0

• x = 2, 3

• x = -2, -3

• { 2, 3 }

• x = -2, 3

Solve for the values of x:

(2x - 1)(x + 4) = 0

• x = 1/2, -4

• x = 1/2, 4

• x = 2, -4

• x = -2, 4

Find the zeros of this quadratic.

• b=4/5, b=3
• b=4, b=-3
• b=1/5, b=3
• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

Solve
(4a + 3)(4a - 3) = 0

• a = ^-3/₄, ³/₄ 
• a = ^-4/₃, ⁴/₃ 
• a = ^-9/₁₆, ⁹/₁₆ 
• a = ^-16/₉, ¹⁶/₉ 

Tags

CCSS.HSA-REI.B.4B

Determine the values of
a, b, and c for
the quadratic equation: 
4x² – 8x = 3

• a = 4, b = -8, c = 3
• a = 4, b =-8, c =-3
• a = 4, b = 8, c = 3
• a = 4, b = 8, c = -3

Use the quadratic formula to solve 2x² + 2x - 12?

• x = -2, 3

• x = 2, 3

• x = 2, -3

• x = -2, -3

• A
• B
• C
• D

Tags

CCSS.HSA-REI.B.4B

• A
• B
• C
• D

Tags

CCSS.HSA-REI.B.4B

• A
• B
• C
• D

Tags

CCSS.HSA-REI.B.4B

• A
• B
• C
• D

Tags

CCSS.8.EE.A.2