Linear Equalities

-12 + c = 38

• c = -19/6
• c = -456
• c = 26
• c = 50

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

10 = -7 + b

• b = -17
• b = 3
• b = 17
• b = -3

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

33 = 4a - 7

• a=-10
• a=10
• a=4.5

Tags

CCSS.7.EE.B.4A

26 = 5a + 1

• a= 5 ⁴∕₅
• a= no solution
• a= 0
• a= 5

Tags

CCSS.7.EE.B.4A

26 = 5a + 1

• a= 5 ⁴∕₅
• a= no solution
• a= 0
• a= 5

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

What is the first step in solving the equation?

• Add 4 to each side
• Subtract 4 from each side
• Subtract 2y from each side
• Divide each side by 2y

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.7

• One of the steps for this problem is to subtract 3 from both sides.
• One of the steps for this problem is to add 4 on both sides.
• One of the steps for this problem is to subtract 4 from both sides.
• One of the steps for this problem is to multiply by -15 on both sides.

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

To create a zero pair with -5, what would we do?

• Add 5
• Subtract 5
• Divide by -5
• Divide by 5

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.7

CCSS.6.NS.C.5

Cheryl gets paid $8 per hour for her job at the record store and $15 for working late on Saturday.  She made a total of $96 last week.  Which equation models this situation?

• 96h + 15 = 8
• h/96 = 8
• 8h + 15 = 96
• h/8 = 96

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.6

CCSS.6.EE.B.7

CCSS.6.EE.C.9

-(n - 8) = -2

• 6
• 10
• -10
• -6

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.5

CCSS.6.EE.B.6