Unit 2 Solving Equations and Inequalities Review

5x + 3y = -2

3x + 2y = -1

• (-1,1)

• (1,-1)

• (-1,2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Jasmine begins solving this problem by combining like terms.

3x + 5x = 10

Which problem begins the same way?

• 5x = 20

• 2(x + 5) = 20

• x/4 = 30

• 4x − 2x = 10

Tags

CCSS.HSA.REI.A.1

Which describes the process that could be used as the first step in solving this equation?

6x = 4 + 5(x + 8)

• Combine like terms by adding 4 + 5.

• Use distributive property to multiply 5(x + 8).

• Use division property of equality to divide both sides of the equation by 6.

• Use subtraction property of equality to subtract 6x from both sides of the equation.

Consider the sequence of steps to solve the equation:

2(x − 4) + 5x = 9x − 10

Given ⇒ 2(x − 4) + 6x = 9x − 10

Step 1 ⇒ 2x − 8 + 6x = 9x − 10

Step 2 ⇒ 2x + 6x − 8 = 9x − 10

Step 3 ⇒ 8x − 8 = 9x − 10

Step 4 ⇒ 8x − 8x − 8 = 9x − 8x − 10

Step 5 ⇒ 0 − 8 = x − 10

Step 6 ⇒ −8 = x − 10

Step 7 ⇒ −8 + 10 = x − 10 + 10

Step 8 ⇒ 2 = x + 0

Step 9 ⇒ 2 = x

Which step in solving this equation is justified by the Distributive Property?

• Step 1 ⇒ 2x − 8 + 6x = 9x − 10

• Step 2 ⇒ 2x + 6x − 8 = 9x − 10

• Step 3 ⇒ 8x − 8 = 9x − 10

Solve the equation for x.

2/3(6 − 9x) = 16

• -2

• -4

• -9

Tags

CCSS.7.EE.B.4A

Which inequality's solution is graphed here?

• x + 9 < 5

• x - 5 < 9

• x + 5 < 9

Tags

CCSS.7.EE.B.4B

Identify a possible first step using the elimination method to solve the system and then find the solution to the system.

3x + 2y = 24

6x + 2y = 30

• Multiply second equation by 2, solution (2, 9).

• Multiply first equation by -2, solution (2, 9).

• Multiply second equation by 2, solution (2, -9).

• Multiply first equation by -2, solution (2, -9).

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Jillian is solving the system of equations using elimination. Her work is shown. What should be her next step.

• x − 5(−1) = 10

• 3(1) + 3y = 12

• 4x - 2(1) = 22

• She is done as she has solved the system.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Identify the graphed linear equation.

• y = 4x + 1

• y = 4x - 1

• y = -4x + 1

• y = -4x - 1

Tags

CCSS.8.F.B.4

CCSS.HSF.LE.A.2

A: 5x − 2y = 10

B: 4x + 3y = 7

To solve this system of equations by elimination, what could you multiply each equation by to cancel out the y-variable?

• Multiply A by 3 and B by 2

• Multiply A by 4 and B by 3

• Multiply A by 3 and B by −4

• Multiply A by −2 and B by 4

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6