Math 1 Midterm review

Is the relation a function? Why.

• Yes, because the x-value 11 has two y-values pair with it.
• Yes, because each x-value has only one y-value paired with it.
• No, because the x-value 11 has two y-values pair with it.
• No, because each x-value has only one y-value paired with it.

Tags

CCSS.8.F.A.1

Is this graph a function or not a function? 

• Function
• Not a Function 

Tags

CCSS.HSF.IF.B.5

CCSS.HSF.IF.A.1

What is the domain of the graph?

• y≥1
• x ≥ 1
• All real numbers
• none of these

Tags

CCSS.8.F.A.1

CCSS.HSF.IF.B.5

What is the range of the graph?

• y≥1
• x≥1
• All real numbers
• none of these

Tags

CCSS.8.F.A.1

CCSS.HSF.IF.B.5

What is the domain of the graph?

• -7 ≤ x < 5
• -3 ≤ x < 1
• -3 ≤ y < 1
• -7 ≤ y < 5

Tags

CCSS.8.F.A.1

CCSS.HSF.IF.B.5

What is the range of the graph?

• -7 ≤ x < 5
• -3 ≤ x < 1
• -3 ≤ y < 1
• -7 ≤ y < 5

Tags

CCSS.8.F.A.1

CCSS.HSF.IF.B.5

• {1, 2, 3, 4, 5}
• {-1, 1, 2, 3}
• {1, 2, 3, 5}
• [1, 5]

Tags

CCSS.8.F.A.1

CCSS.HSF.IF.B.5

Create a rule for the sequence:
6, 2, 2/3, 2/9

• a_n=6(1/3)^n-1
• a_n= 6-4n
• a_n= 6(-1/3)^n-1
• a_n= (-1/3)6^n-1

Tags

CCSS.HSF.BF.A.2

Create a rule for the sequence:
-3, 6, -12, 24,,,

• a_n= -3+ 2n
• a_n= -3(-2)^n-1
• a_n= -2(-3)^n-1
• a_n= -3(2)^n-1

Tags

CCSS.HSF.BF.A.2

Given a₁= 6 and d= -.5 find a _n

• f(n)= 6 - (.5)n
• f(n)= 6.5 + (.5)n
• f(n)= 6.5 - (.5)n
• f(n)= .5 - 6n

Tags

CCSS.HSF.BF.A.2