Coordinate Geometry Exam Review

For points A (3, -2) and B (1, 6) find:

The distance from A to B.

You do not need to simplify.

• Square root of 12

• Square root of 20

• Square root of 60

• Square root of 68

Tags

CCSS.HSG.GPE.B.7

For points A (3, -2) and B (1, 6) find:

The midpoint of [AB].

• (2, 2)

• (4, 4)

• (1, -4)

• (4, 2)

Tags

CCSS.HSG.GPE.B.6

For points A (3, -2) and B (1, 6) find:

The coordinates of point C if B is the midpoint of [AC].

• (2, 2)

• (5, 10)

• (-1, 14)

• (-2, 8)

Tags

CCSS.HSG.GPE.B.6

Two lines have gradients, (4/d) and (-2/5).

Find d if the lines are: perpendicular

• d = 5 / 8

• d = 8 / 5

• d = -10

• d = 10

Tags

CCSS.8.EE.B.6

Two lines have gradients, (4/d) and (-2/5).

Find d if the lines are: parallel.

• d = 5 / 8

• d = 8 / 5

• d = -10

• d = 10

Tags

CCSS.8.EE.B.6

Find the gradient and the y-intercept of the equation:

y = (x+2)/3

(red is the numerator, green is the denominator)

• m = (1/3) , y-intercept: (0, 2/3)

• m = 1 , y-intercept: (0, 2/3)

• m = (1/3) , y-intercept: (0, 2)

• m = 3 , y-intercept: (0, 2/3)

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Find the gradient and the y-intercept of the equation:

3x + 2y = 8

• m = (-2/3) , y-intercept: (0, 4)

• m = (-3/2) , y-intercept: (0, 4)

• m = (-3/2) , y-intercept: (4, 0)

• m = (3/2) , y-intercept: (0, 4)

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Find the equation of the line in gradient-intercept form (slope-intercept) with a gradient of 5 and y-intercept of -2.

• y = -2x + 5

• y = 2x + 5

• y = 5x + 2

• y = 5x - 2

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Find the equation of the line in gradient-intercept form (slope-intercept) with a gradient of (3/4) and passing through the point: (3, -1).

• y = (3/4)x + (13/4)

• y = (3/4)x - (13/4)

• y = (3/4)x - 13

• Correct answer, this is not.

Find the equation of the line in general form, Ax + By = C, passing through the points (4, -3) and (-1, 1).

• 4x + 5y = 5

• 4x - 5y = -1

• 4x + 5y = 1

• Up, you must look, for the answer you seek.